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enyata [817]
3 years ago
6

Divide a 7 inch line into three parts so that each part is longer than than the one before it

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0
The answer is 2.33 when you multiply bi 3 its 6.99
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heat energy

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water in the sun begins to get hot

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How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
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Convert units of a given substance to moles.

Using the mole ratio, calculate the moles of substance yielded by the reaction.

Convert moles of wanted substance to desired units.

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Sulfur hexafluoride is represented by
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Elagas

Esaflon
Sulfur(VI) fluoride

Sulfuric fluoride
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A supersaturated solution holds less solute than it normally can.
NeTakaya

A supersaturated solution holds less solute than it normally can is false. It actually contains more solute that it normally can. Having less solute than it normally can is an unsaturated solution. And when it has the exact amount of solute, it is a saturated solution.

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