Answer:
I hope this is it. I'm not really sure.
Answer: The answer is Fossil A is younger than the index fossil.
Explanation: Because it’s the newest layer
Answer: 116g/mole
Explanation:
She didn't get the answer because she didn't add the them well , due to the bracket present.
Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol
Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.
W are given a chemical reaction:
![Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)](https://tex.z-dn.net/?f=Mg%28s%29%2B%5Cfrac%7B1%7D%7B2%7DO_2%28g%29%5Crightarrow%20MgO%28s%29)
![c=5760J/^oC](https://tex.z-dn.net/?f=c%3D5760J%2F%5EoC)
![\Delta T=0.570^oC](https://tex.z-dn.net/?f=%5CDelta%20T%3D0.570%5EoC)
To calculate the enthalpy change, we use the formula:
![\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J](https://tex.z-dn.net/?f=%5CDelta%20H%3Dc%5CDelta%20T%5C%5C%5C%5C%5CDelta%20H%3D5760J%2F%5EoC%5Ctimes%200.570%5EoC%3D3283.2J)
This is the amount of energy released when 0.1326 grams of sample was burned.
So, energy released when 1 gram of sample was burned is = ![\frac{3283.2J}{0.1326g}=24760.181J/g](https://tex.z-dn.net/?f=%5Cfrac%7B3283.2J%7D%7B0.1326g%7D%3D24760.181J%2Fg)
Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:
![\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%3D24760.181J%2Fg%5Ctimes%2024g%2Fmol%5C%5C%5C%5C%5CDelta%20H%3D594244.3J%2Fmol%5C%5C%5C%5C%5CDelta%20H%3D594.244kJ%2Fmol)
Because many animals are likely to die from contamination