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3 years ago

Which of these represents a compound ? * Water Hydrogen Oxygen

Chemistry

2 answers:

fiasKO [112]3 years ago

8 0

Answer:

water

Explanation:

H2O

PilotLPTM [1.2K]3 years ago

3 0

Answer:The answer is water

Explanation: Hydrogen is an element made of an aggregate of hydrogen atoms while oxygen is an element made of oxygen atoms. However, water is a compound made of water molecules.

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What prefix should be used to name a hydrocarbon that has a six-carbon parent chain?a.hex- b.meth- c.non- d.sept-

liberstina [14]

A. hex- Normally with 6, the prefix is hex-. For example a polygon having 6 sides is known as hexagon.

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3 years ago

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AlekseyPX

Answer:

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3 0

3 years ago

Identify ALL the possible mol ratio from<br> this balanced equation:

grandymaker [24]

Answer:

$\frac{1 mole of N_{2} }{3 moles of H_{2} }$

Explanation:

The equation of the reaction:

Nitrogen gas N₂ reacts with Hydrogen as H₂ to produce ammonia NH₃;

N₂ + H₂ → NH₃

The balanced equation is ;

N₂ + 3H₂ → 2NH₃

The mole ratio is the ratio of the coefficients of the combining reactants;

1 mole of N₂ combines with 3 mole of H₂;

So;

$\frac{1 mole of N_{2} }{3 moles of H_{2} }$

3 0

3 years ago

HELPPp now plsss I really need help !!!!!

blondinia [14]

Answer:

The Forces that form each star would be your answer :)

5 0

3 years ago

A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7

Hitman42 [59]

Answer:

$P_{tot}=465.27torr$

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

$n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol} =2.00mol$

Next, we calculate such mole fraction as follows:

$x_{O_2}=\frac{2}{6.93+3+2} =0.168$

Then, given the following equation:

$P_{O_2}=P_{tot}*x_{O_2}$

So we solve for the total pressure as follows:

$P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr$

Regards!

6 0

3 years ago