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andriy [413]
3 years ago
12

Someone please help me figure this out!

Chemistry
1 answer:
Aliun [14]3 years ago
4 0
Hey!!

here is your answer >>>

let us multiply the two numbers above!. we get,

(7.51)(6.50) ( 10) / 1.62 (10 )^-6

(7.51)(6.5)(10)^7/1.62

(751)(650)(10^3) / 1.62

301327.160 (10^3)

301327160 is the number.

Hope my answer helps!
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How many moles of nitrogen gas are present in a 28.9 dm3 temperature of 55.0 °C and a pressure of 144 kPa?
jeka57 [31]

Given :

Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .

Volume of container, V = 28.9 dm³ = 0.0289 m³ .

Pressure, P = 144 kPa = 144000 Pa .

To Find :

Number of moles of nitrogen  gas.

Solution :

We know, by ideal gas equation :

PV = nRT  ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .

n = \dfrac{PV}{RT}\\\\n = \dfrac{144000\times 0.0289}{8.31 \times 328} \ moles\\\\n = \dfrac{4161.6}{2725.68}\\\\n = 1.53 \ moles

Therefore, number of moles of nitrogen gas is 1.53 moles.

8 0
3 years ago
Ice usually forms on the top part of lakes not the bottom , the reason for this occurence is?​
Bingel [31]

Answer:

Ice is less dense than water because of the way it forms a hexagonal crystalline structure. Each water molecule consists of two hydrogen atoms bonded to the bottom of an oxygen atom. ... In the winter, temperatures in a lake get close enough to freezing that the colder water is less dense and floats to the top

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3 years ago
If your end product is 200.0 g KMnO4 how much KOH did you start with?
aniked [119]

Answer:

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Explanation:

Hello there!

In this case, according to the following chemical reaction we found on goo gle as it was not given:

2MnO_2+4KOH+O_2\rightarrow 2KMnO4+2KOH+H_2

Whereas we can see a 2:4 mole ratio of potassium permanganate product to potassium hydroxide reactant with molar masses of 158.03 g/mol and 54.11 g/mol respectively. In such a way, by developing the following stoichiometric setup, we obtain the mass of KOH to start with:

m_{KOH}=200.0gKMnO_4*\frac{1molKMnO_4}{158.03gKMnO_4}*\frac{4molKOH}{2molKMnO_4}  *\frac{56.11gKOH}{1molKOH}\\\\m_{KOH}= 142.0gKOH

Best regards!

8 0
3 years ago
Anhydrous aluminium chloride contain 20.2% by mass of aluminium show that the emprical formula for anhydrous aluminium chloride​
Usimov [2.4K]

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3 years ago
What is the oxidation number of sulfur in na2s2o3 ?.
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Answer:

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