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Novosadov [1.4K]
3 years ago
13

Secondary bile salts lack a hydroxyl (OH) group when compared to primary bile salts. What is the consequence of the loss of this

group?
Chemistry
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

When secondary bile salts (or acids) lack a OH, they are reabsorbed

Explanation:

The lost of a hydroxyl group (OH) in the bile salts structure means less hydro solubility. Thus, they are not eliminated, conversely, the are reabsorbed for intestine and they go back to the liver.

I hope my answer helps

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Does the volume change if a ballon is put in a freezer
Lorico [155]
It gets smaller so yes
6 0
3 years ago
Which of the following is the valence elec- tronic structure for a halogen? 1. n s1 2. n s2 3. n s2 n d10 4. n s2 n p5 5. n s2 n
Arturiano [62]

Answer: option 4. ns² np⁵

Explanation:

The <em>valence electronic structure</em> of the compounds is the distribution of the valence electrons, i.e. the outermost electrons of the atoms.

The distribution of the electrons in the atomic orbitals is named electron configuration.

Each element has a proper electron configuration which is determined according to a series of rules: lowest orbital energy, Pauli's exclusion principle and Hund's rule.

The valence electronic structure of the atoms is related with the period (column of the periodic table) to which the element belongs.

Each period has a characteristic <em>valence structure</em> (number and location of the outermost electrons). It is this structure what conferes the elements of a same period (column in the periodic table) their similar chemical properties.

This table summarizes the <em>valence eletronic structure </em>of the representative elements:

<u>Period (column)    name         number of valence eletrons    Structure</u>

1                        Alkali metals                             1                             ns¹

2                       Alkaline earth metals               2                            ns²

13                                                                        3                            ns² np¹

14                                                                        4                            ns² np²                                          

15                      Pnictogens                               5                             ns² np³                                                                                        

16                      Chalcogens                              6                             ns² np⁴

17                      Halogens                                  7                             ns² np⁵

18                      Noble gases                             8                            ns² np⁶

There you can see that the <em>halogens</em> belong to the period 17, have 7 valence electrons, and their<em> valence electrons are have the structure ns² np⁵.</em>

This is the specific valence electronic structure for the first five halogens:

<u>Halogen      atomic number      row (n)   period   valence electronic structure</u>

Fluor               9                             2            15                  2s² 2p⁵

Chlorine        17                             3            15                  3s² 3p⁵

Bromine        35                            4            15                  4s² 4p⁵

Iodine            53                            5            15                  5s² 5p⁵

Astatine        85                            6             15                 6s² 6p⁵

There you see the common <em>structre ns² np⁵.</em>

8 0
4 years ago
Science-DNA Codes. Fill out the chart.
MissTica

Answer: (not sure)

T - A  

T - A

T - A

A - T

C - G

G - C

C - G

C - G

A - T

im not sure about the amoni acid produced but

AAA produces -> Lys.

ACG produces -> Thr.

and i don't know about the last one

7 0
3 years ago
Read 2 more answers
Solution a is a 1.0 m solution with a nonionic solute and water as the solvent. solution b is a 1.0 m solution with the same non
solniwko [45]
<span>The solution of ethanol will have the greatest increase in boiling point.
   The formula for boiling point elevation is:
 Î”Tb = Kb · bB
 where
 Î”Tb = boiling point elevation
 Kb = ebullioscopic constant for the solvent
 bB = molarity of the solution
   Since in the solute is nonionic, we don't have to worry about the molecules of the solute breaking up into multiple ions, thereby increasing the effective molarity of the solution. So which ever solvent has the highest ebullioscopic constant, will have the greatest increase in boiling point. This constant can be calculated by the equation:
 Kb = RTb^2M/ΔHv
 where
 R = Ideal gas constant
 Tb = boiling point of pure solvent
 M = Molar mass of solvent
 Î”Hv = heat of vaporization per mole of solvent
   For our purposes, we can ignore the idea gas constant, and instead look at only the boiling point, molar mass, and heat of vaporization. Then calculate Tb^2M/ΔHv So let's do so:
 (Note: Not bothering to be precise in molar mass. If the end result is close, then I'll bother. Otherwise, just using nice round numbers).
   Water
 Boiling point: 373.15 K
 Molar mass: 18 g/mol
 heat of vaporization: 40660 J/mol
 Tb^2M/ΔHv: 61.64
   Ethanol
 Boiling point: 351.52 K
 Molar mass: 46 g/mol
 heat of vaporization: 38600 J/mol
 Tb^2M/ΔHv: 147.26
   The value of Tb^2M/ΔHv is significantly greater for ethanol than it is for water (by more than 2 to 1), so it will have the greatest increase in boiling point.</span>
4 0
3 years ago
Read 2 more answers
The heat of solution is found by adding a salt to water in a calorimeter and measuring the temperature change. The specific heat
melomori [17]

Answer:

The heat of the solution of salt is 1.66.11 J/g.

Explanation:

Mass of the water = m = 46.52 g

Initial temperature of the water = T_1=22.83 ^oC

Final temperature of the water = T_2=18.98^oC

The specific heat of water, c = 4.180 J/gºC

Heat associated with water on dissolving salt: q

Q=mc(T_2-T_1)

Q=46.52 g\times 4.180 J/g&oC\times (18.98^oC-22.83 ^oC)

Q=-748.65 J

Negative sign means that heat was lost by water on an addition of a salt.

Heat released on dissolving of salt = -Q = 748.65 J

Mass of salt added = 4.5069 g

Heat of the solution of salt :

= \frac{-Q}{ 4.5069 g}=\frac{748.65 J}{ 4.5069 g}=1.66.11 J/g

The heat of the solution of salt is 1.66.11 J/g.

5 0
4 years ago
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