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Novosadov [1.4K]
3 years ago
13

Secondary bile salts lack a hydroxyl (OH) group when compared to primary bile salts. What is the consequence of the loss of this

group?
Chemistry
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

When secondary bile salts (or acids) lack a OH, they are reabsorbed

Explanation:

The lost of a hydroxyl group (OH) in the bile salts structure means less hydro solubility. Thus, they are not eliminated, conversely, the are reabsorbed for intestine and they go back to the liver.

I hope my answer helps

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Answer:

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3 years ago
Phenol, c6h5oh, is a stronger acid than methanol, ch3oh, even though both contain an o]h bond. Draw the structures of the anions
timurjin [86]

In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure.  They are created by moving electrons in double or triple bonds, and not atoms.

Phenol, C_6H_5OH and methanol, CH_3OH both are alcohols  that contain an -OH group attached to carbon atom.

Due to loss of 1 H from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1 H it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.

The structures of the anions resulting from loss of 1 H from phenol and methanol is shown in the image.

8 0
3 years ago
When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0
3 years ago
How many moles of NaOH must be dissolved in 1.00 L of water to make NaOH (aq) with a pH of 12.2?
adelina 88 [10]

Answer:

1.58 102 mol

Explanation:

I just looked it up on Quizlet.

6 0
3 years ago
Why is cellulose so difficult for most animals to digest?
NNADVOKAT [17]
The answer is C .Cellulose is a long chain of glucose and to be able to use any of the energy stored in them an organism must break it down into single glucose molecules, and this is why most animals go for a different diet. The chain is very difficult to break down and must be treated with concentrated acids at high temperature. This is a hard task to do and often time needs many stomachs.

3 0
3 years ago
Read 2 more answers
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