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Novosadov [1.4K]

3 years ago

13

Secondary bile salts lack a hydroxyl (OH) group when compared to primary bile salts. What is the consequence of the loss of this

group?

1 answer:

Slav-nsk [51]3 years ago

7 0

Answer:

When secondary bile salts (or acids) lack a OH, they are reabsorbed

Explanation:

The lost of a hydroxyl group (OH) in the bile salts structure means less hydro solubility. Thus, they are not eliminated, conversely, the are reabsorbed for intestine and they go back to the liver.

I hope my answer helps

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What is the net force of the plane

ExtremeBDS [4]

Answer: The difference between the opposing forces; lift minus weight, or thrust minus drag.

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3 years ago

MAVERICK [17]

Answer:

C

Explanation:

energy cannot be created or destroyed like solar energy for instance. it is already energy because it comes from the sun and for other reason.

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3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

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3 years ago

Why all samples of a given substance have the same intensive properties?

Karolina [17]

Answer:

Every sample of a given substance has identical intensive properties because every sample has the same composition

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3 years ago

O2- is the Lewis ______ in the following reaction

matrenka [14]

$O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the $O^{2-}$ is the lewis base which is donating an electron pair to the central atom of $SO_3$ to form $SO_4^{-2}$ .

Hence, $O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

Learn more about the lewis base here:

brainly.com/question/15570523

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3 0

2 years ago