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3 years ago

The light rays in the illustration below do not properly focus at the focal point. this problem occurs with?

Physics

1 answer:

tankabanditka [31]3 years ago

7 0

Answer:

The problem occurs with all spherical mirrors.

Spherical mirrors are practical up to about inches in diameter.

Reflecting telescopes use spherical mirrors for apertures up to about 4 ".

Larger aperture telescopes use parabolic mirrors to obtain sharp focus.

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3 years ago

Which of the following point towards the center of the circle in uniform circular motion?

Luba_88 [7]

Answer: E) Acceleration, net force

Explanation: In order to explain this problem we have to consirer that the uniform circulat motion has constant angular velocity (ω) and the vector velocity is changed its direction for any point that cover the circle but its modulus is contant and its value is v=ω*R. In order to ensure these conditions, the net force also the accelaration called centripetal must point to the center of the circular trajectory.

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4 years ago

Two negative charges that are both -3.0 C push each other apart with a force of 19.2 N. How far apart are the two charges ?

fgiga [73]

The Coulomb's force acting between two charges is
$F=k_e \frac{q_1 q_2}{r^2}$
where $k_e = 8.99 \cdot 10^9 N m^{-2}C^{-2}$ is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.

Using $q_1 = q_2 = -3 C$ , we can find the distance between the two charges when the force is F=19.2 N:
$r= \sqrt{k_e \frac{q_1 q_2}{F} }= \sqrt{ 8.99\cdot 10^9 \frac{(-3.0C)^2}{19.2 N} }=6.5 \cdot 10^4 m = 65 km$

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3 years ago

A 75-kilogram hockey player is skating across the ice at a speed of 6.0 meters per second. What is the magnitude of the average

saveliy_v [14]

Answer:

(3) 690 N

Explanation:

Force: This is the product of mass and acceleration of a body. The S.I unit of force is Newton(N).

The formula for force is given as,

F = ma..................... Equation 1

Where F = force, m = mass, a = acceleration.

Also,

a = (v-u)/t................... Equation 2

Where v = Final velocity, u = initial velocity, t = time.

Given: u = 6.0 m/s, v = 0 m/s (bring to stop), t = 0.65 s.

Substitute into equation 2

a = (0-6)/0.65

a = -6/0.65

a = -9.23 m/s²

Also given: m = 75 kg

Substitute again into equation 1

F = 75(-9.23)

F = -692.25 N

The negative sign tells that the force oppose the motion of the player

F ≈ 690 N

Hence the right option is (3) 690 N

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4 years ago