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3 years ago

The light rays in the illustration below do not properly focus at the focal point. this problem occurs with?

Physics

1 answer:

tankabanditka [31]3 years ago

7 0

Answer:

The problem occurs with all spherical mirrors.

Spherical mirrors are practical up to about inches in diameter.

Reflecting telescopes use spherical mirrors for apertures up to about 4 ".

Larger aperture telescopes use parabolic mirrors to obtain sharp focus.

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A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launch

Lina20 [59]

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_{o}cos \theta t$ ----------------------(1)

$y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}$ ---------(2)

$V=V_{o}-gt$ ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

$V_{o}$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

t is the time

y is the final height of the ball

$y_{o}$ is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

$t=\sqrt{\frac{2 y_{o}}{g}}$

$t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}$

$t=1.597$ s

Substituting (6) in (1):

$67.1 =V_{o} cos(0\°) 1.597$ -------------------(4)

Step 2: Finding $V_{o}$ :

From equation(4)

$67.1 =V_{o}(1) 1.597$

$V_0 = \frac{6.71}{1.597}$

$V_{o}=42.01$ m/s (8)

Substituting $V_{o}$ in (3):

$V=42.01 -(9.8)(1.597)$

v =42 .01 - 15.3566

V=26.359 m/s

5 0

3 years ago

The answer would be ?

Cerrena [4.2K]

Answer:

D. demand; increased

Explanation:

Demand is how much people want it.

4 0

3 years ago

A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma

Dahasolnce [82]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{38}{57} = \frac{2}{3} \\ = 0.666666...$

We have the final answer as

Hope this helps you

4 0

3 years ago

Which instrument is used to measure liquid volume?

Alecsey [184]

Volumetric cylinders and volumetric flasks

3 0

3 years ago

Read 2 more answers

I am the particle that is so small that scientists treat me as though I have no mass. Scientists also figure that I probably spe

tatyana61 [14]

Answer:

its electrons

Explanation:

only electrons stays outside the nucleus unlike protons and neutrons and it has little to no mass

8 0

3 years ago