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UNO [17]
3 years ago
14

700 students attend Ridgewood Junior High School. 5% of students bring tlieir lunch

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

35

Step-by-step explanation:

bc if u change the 5% into .05 than u multiply it to get 35 sorry if I am wrong or to late

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Math graph equation. <br> (Picture.)
vladimir1956 [14]

Answer:

y = -2x + 3 is the required equation

Step-by-step explanation:

From the graph we will get two ordered pairs

If we see that When x=0 then y=3  and when x = 1 then  y=1

Now from this we can find the slope of the Graph

So slope of graph = (y2 - y1) / (x2-x1)

                               =(1-3) / (1-0)

                                =-2

So

Slope = m = -2

Now the equation is

y = mx + b

We have to find the value of b

as we have two ordered pairs we can take any of it to find the value of b because line passes through those points

taking (0,3) as a point

y= mx + b

put values

3 = -2*(0) + b

so

b=3


Now the equation of the line in this form is

y = mx + b

which is

y = -2x + 3

5 0
3 years ago
Please answer question. I need some math to explain the answer, not just the answer. Ignore my work, that was wrong. Please help
Virty [35]
The correct answer to your question is number 2
3 0
3 years ago
What is the greatest common factor if 32 and 40? A) 5 B) 8 C) 40 D) 2
tensa zangetsu [6.8K]
8. It is divisible by both 32 and 40.
5 0
3 years ago
Read 2 more answers
The distance between two locations, A and B, is calculated using a third location C at a distance of 15 miles from location B. I
Jobisdone [24]
We will first calculate ∠A:
∠∠A = 180° - ( 105° + 20 ° ) = 180° - 125° = 55°
Then we will use the Sine Law:
15 / sin 55° = AB / sin 20°
15 / 0.81915 = AB / 0.342
AB · 0.81915 = 15 · 0.342
AB · 0.81915 = 5.13
AB = 5.13 : 0.81915
AB = 6.26 ≈ 6.3 miles
Answer: The distance between the locations A and B is 6.3 miles.
4 0
3 years ago
Read 2 more answers
Show the work please
Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0
3 years ago
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