Answer:
a = -8.912 m/s²
Explanation:
Given,
The initial velocity of the car, u = 28 m/s
The final velocity of the car, v = 0
The distance traveled by car, d = 88 m
The velocity displacement relation is given by the formula
v = d/t
∴ t = d/v
Substituting in the above values in the given equation
t = 88/28
= 3.142 s
The acceleration is given by the formula
a = (v-u)/t
= (0 - 28)/3.142
= -8.912 m/s²
The negative sign is that the car is decelerating.
Hence, acceleration a = -8.912 m/s²
Answer:
around 50 miles per hour is the answer i believe :)
Explanation:
Answer:
i really hope this helps "One of the advantages of parallel circuits is that they ensure all components in the circuit have the same voltage as the source. For instance, all bulbs in a string of lights have the same brightness."
Explanation:
Position of paul with respect to john is given as
14 m due west of john
position of George with respect to Paul is given as 36 m in direction 37 degree south of east
now we need to find the position of George with respect to John
![r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j](https://tex.z-dn.net/?f=r_%7BGJ%7D%20%3D%20r_G%20-%20r_j%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3Enow%20for%20the%20above%20equation%20we%20can%20add%20the%20two%20equations%3C%2Fp%3E%3Cp%3E%5Btex%5Dr_%7BGj%7D%20%3D%20-14%5Chat%20i%20%2B%2036%20cos37%5Chat%20i%20-%2036sin37%5Chat%20j)
so the magnitude is given as
and direction is given as
<em>so it is 26.2 m at an angle 55.75 degree South of east</em>
Stopped at the end of the tracks by a spg-damper system, as shown in fig. 1
