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3 years ago

5

A railroad car of mass 2,000 kg traveling at a velocity v = 10 m/s is stopped at the end of the tracks by a spring-damper system

, as shown in fig. 1. if the stiffness of the spring is k = 80 n/mm and the damping constant is c = 20 n-s/mm, determine:

1 answer:

Murrr4er [49]3 years ago

6 0

Stopped at the end of the tracks by a spg-damper system, as shown in fig. 1

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It takes the Moon 27.3 days to complete a single orbit around Earth.

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The depth of the liquid is 10 cm and the radius of the cylinder is 3.0 cm. The weight of

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A car travelling at 40 m/s comes to a halt in 8 seconds. What is the car’s acceleration and how far does it travel while it is s

IrinaVladis [17]

Answer: Acceleration = 5m/s^2; Distance traveled = 320 m

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Velocity of car = 40m/s

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Acceleration = ?

Distance traveled = ?

A) Since acceleration is the rate of change of velocity per unit time

i.e acceleration = velocity / time

acceleration = 40m/s / 8 seconds

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B) To get how far the car traveled before stopping, obtain the distance from the formula:

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3 years ago

Anastasy [175]

nAnswer:

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3 years ago

Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?

Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = $\frac{1}{f}$

where

f = focal length

Thus

f = $\frac{1}{P}$

f = $\frac{1}{2}$ = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

$\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}$

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

$\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}$

$\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}$

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

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3 years ago