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3 years ago

You are trying to determine how far from a victim a shot took place. What factor would most interfere with your analysis?

Chemistry

2 answers:

zheka24 [161]3 years ago

7 0

<h2>Answer: i agree B</h2><h2>Explanation:</h2>

A the gun wasn't found. this would be an issue but still possible to determine distance with gunpoweder residue

C a hollow point round was used. that is just some type of bullet. i dont remember any specific lesson on bullet identification

D the gun was decades old. this could also be an issue, but it doenst have anything to do with distance

So it must be B. unless the victim could tell you how far the shooter was. but then we would have to consider consciousness, if the victim was facing the shooter, and if the victim was sober. but that's juts overthinking things. it 's most likely B

Likurg_2 [28]3 years ago

3 0

I would think 2. The victim survived the incident because the victim would have moved or gotten up, which changes the distance between the victim and the gun.

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If a 0.320 mM solution of MnO41- has an absorbance of 0.480 at 525 nm in a 1.000 cm cell. What is the concentration of a MnO41-

larisa [96]

Answer:

Hence the concentration of a MnO41- solution that has absorbance of 0.490 in the same cell at that wavelength is 0.3266.

Explanation:

Now A = el, el=const

Then,

$A2 / A1 = C2/ C1\\\\0.49/ 0.48 = C2 / 0.32\\\\C2 = 0.3266$

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3 years ago

Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.

kupik [55]

The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,

2H2 + O2 --> 2H2O

The masses of each of the reactants are calculated below.

2H2 = 4(1.01 g) = 4.04 g
O2 = 2(16 g) = 32 g

Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
(1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2

Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.

<em>Answer: 1.22 g of oxygen</em>

4 0

3 years ago

A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o

Andreas93 [3]

<h3>Answer:</h3>

2.809 L of H₂SO₄

<h3>Explanation:</h3>

Concept tested: Moles and Molarity

In this case we are give;

Mass of solid sodium hydroxide as 13.20 g

Molarity of H₂SO₄ as 0.235 M

We are required to determine the volume of H₂SO₄ required

<h3>First: We need to write the balanced equation for the reaction.</h3>

The reaction between NaOH and H₂SO₄ is a neutralization reaction.
The balanced equation for the reaction is;

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

<h3>Second: We calculate the umber of moles of NaOH used </h3>

Number of moles = Mass ÷ Molar mass
Molar mass of NaOH is 40.0 g/mol

Therefore;

Moles of NaOH = 13.20 g ÷ 40.0 g/mol

= 0.33 moles

<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>

From the equation, 2 moles of NaOH reacts with 1 mole of H₂SO₄
Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
Thus, Moles of H₂SO₄ = moles of NaOH × 2

= 0.33 moles × 2

= 0.66 moles of H₂SO₄

<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>

When given the molarity of an acid and the number of moles we can calculate the volume of the acid.

That is; Volume = Number of moles ÷ Molarity

In this case;

Volume of the acid = 0.66 moles ÷ 0.235 M

= 2.809 L

Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.

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4 years ago

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Andreyy89

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Answer:

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