We can simply find components of the given directions and conveniently add them up to find the total distance.
290 km 20 deg north of east can be decomposed as :
290 x cos(20) EAST + 290 sin(20) NORTH
=272.5 E + 99.18 N
Now from this point ,
170 Km 30 deg west of north :
170 cos(30) N - 170 sin (30) E [ east = - west]
= 147.22 N - 85 E
hence coordinates of lake b are
(272.5 - 85) E + (99.18 + 147.22)N
187.5 E +264.4 N
use right triangle property to find distance D =
D = 324.13 Km
and angle = atan(b/a) = 54.65 deg
hence lake b is at 324.13 Km 54.65 deg east of north
Answer:
7.50 m/s^2
Explanation:
The period of a pendulum is given by:
(1)
where
L = 0.600 m is the length of the pendulum
g = ? is the acceleration due to gravity
In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:
And the period is the reciprocal of the frequency:
And by using this into eq.(1), we can find the value of g:
Answer:
Speed of the alpha particle is
Explanation:
We have given charge on alpha particle
Mass of the alpha particle
Potential difference
We have to find the speed of the alpha particle
From energy conservation we know that