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charle [14.2K]
3 years ago
5

"Synthesis gas" is a mixture of carbon monoxide and water vapor. At high temperature synthesis gas will form carbon dioxide and

hydrogen, and in fact this reaction is one of the ways hydrogen is made industrially. A chemical engineer studying this reaction fills a tank with of carbon monoxide gas and of water vapor. When the mixture has come to equilibrium he determines that it contains of carbon monoxide gas, of water vapor and of carbon dioxide. The engineer then adds another of carbon monoxide, and allows the mixture to come to equilibrium again. Calculate the moles of after equilibrium is reached the second time. Round your answer to significant digits.

Chemistry
2 answers:
pishuonlain [190]3 years ago
7 0

Answer:

Explanation:

Attached is the solution

Pavlova-9 [17]3 years ago
6 0

Answer:

Check the explanation

Explanation:

Lets start by drawing the ICE chart

reaction is

...............CO + H2O ========= CO2 + H2

I.............2.6.........3.4..........................0................0

E...........1.88........2.68......................0.72............0.72

since reaction is 1 : 1 if 0.72 atm of H2 are produced then the same amount of CO2 will be formed

calculate Kp this is the relationship between the pressure of products and the pressure of reactants

Kp = Pproducts / Preactants = [Pco2* PH2] / [PCO * PH2O]

Kp = 0.72 * 0.72 / (1.88 * 2.68) = 0.1029

Write the ICE chart again

...............CO + H2O ========= CO2 + H2

I.............1.88.........2.68+1.1.................0.72................0.72

C...........-x............. -x..............................+x........................+x

E......1.88 - x...........3.78-x.....................0.72+x..... ..0.72+x

Kp is = (0.72+x)*(0.72+x) /[ (1.88-x)*(3.78-x) ] = 0.1029

lets say that x is the change of pressure.

If you solve this equation you will get a value of x equal to 0.1

Pressure of CO2 is

0.72 + 0.1= 0.82 atm

using 2 sig figures this would be

8.2x10-1 atm

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15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
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The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

<h3>What is the number of moles of gases in the given samples?</h3>

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

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Moles of gas in the given helium gas sample:

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D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

#SPJ1

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