<u>Answer:</u> Both the given species are isotopes of the same element.
<u>Explanation:</u>
An isotope is defined as the chemical species that have the same atomic number but a different mass number.
The atom consists of 3 subatomic particles:
- Protons: They are positively charged particles present in the nucleus of an atom.
- Electrons: They are negatively charged particles present in the orbits around the nucleus of an atom.
- Neutrons: They are neutral particles present in the nucleus of an atom.
An atomic number is defined as the number of protons or number of electrons present in a neutral atom. It remains specific for a particular element.
Mass number is defined as the sum of the number of protons and neutrons present in the nucleus of an atom.
Given values:
<u>For isotope 1:</u>
Number of protons = 11 = atomic number
Number of neutrons = 13
Mass number = 11 + 13 = 24
<u>For isotope 2:</u>
Number of protons = 11 = atomic number
Number of neutrons = 12
Mass number = 11 + 12 = 23
As the atomic number of both the isotopes is the same. Thus, they belong to the same elements.
Your answer is:
A volcano spewing out smoke and gases
__________________________
When volcano erupts, various kinds of substances comes out from the interior of earth. A large amount of gases and smoke also come out and enter into atmosphere. These can adversely affect the weather of the area and lead to many health problems.
1L of 0.5M HCl contains 0.5mol of HCl which can react.
This can be found by the fact that
molarity is defined as the number of moles of a substance per Liter of solution. That means that 0.5M of HCl can be thought of as 0.5moles of HCl per liter of solution.
In general to find the number of moles of substance in a solution using the molarity all you do is multiply the molarity by the volume of the solution (in liters).
I hope this helps. Let me know if anything is unclear.
Answer:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Explanation:
A₃B₈ + C₂ –> AC₂ + B₂C
The equation can be balance as illustrated below:
A₃B₈ + C₂ –> AC₂ + B₂C
There are 3 atoms of A on the left side and 1 atom on the right side. It can be balance by writing 3 before AC₂ as shown below:
A₃B₈ + C₂ –> 3AC₂ + B₂C
There are 8 atoms of B on the left side and 2 atoms on the right side. It can be balance by writing 4 before B₂C as shown below:
A₃B₈ + C₂ –> 3AC₂ + 4B₂C
There are 2 atoms of C on the left side and a total of 10 atoms on the right side. It can be balance by writing 5 before C₂ as shown below:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Now, the equation is balanced.