Question

During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed v0 = 38 m/s at an angle θ = 34° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem.

Answer 1

Answer:

The horizontal distance is 136.6 m.

Explanation:

Given that,

Initial speed = 38 m/s

Angle = 34°

Suppose, Calculate the horizontal distance $x_{max}$ in meters the ball has traveled when it returns to ground level.

We need to calculate the horizontal distance

Using formula of range

$R=\dfrac{v_{0}^2\sin(2\theta)}{g}$

Where, v= speed

g = acceleration due to gravity

Put the value into the formula

$R=\dfrac{(38)^2\sin(2\times34)}{9.8}$

$R=136.6\ m$

Hence, The horizontal distance is 136.6 m.