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expeople1 [14]
3 years ago
14

Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be tre

ated as particles and are fixed with a certain separation. (a) For what value of q/Q will the electrostatic force between the two spheres be maximized? What are the (b) smaller and (c) larger values of q/Q that give a force magnitude that is 75% of that maximum?
Physics
1 answer:
forsale [732]3 years ago
7 0

Answer:

2. Smaller value of q = 1/4Q

3. Larger value of q = 3/4Q

Explanation:

1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.

2. The smaller value is

F = 75% = 75/100

= 3/4 * Q²/16piEod² ---3

When we equate 1 and 3

We get 3Q²/16 = Qq - q² from here we cross multiply to get

3Q² = 16(Qq-q²)

3Q² = 16Qq-16q²

16q² - 16Qq + 3Q² = 0

When solve this out using the quadratic equation formula, we have:

Q/2 +- 2Q/8

We can get the smaller value of q as

Q/2-2Q/8

Solve using LCM we get

2Q/8 = 1/4Q = Q/4

C. The larger value of q

Q/2+2Q/8

= 6Q/8

= 3Q/4

Please use the attachment it will guide you to understand this better.

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3 years ago
What is an Environmental Footprint?
Mariana [72]

Answer: The measurement of human demand on nature is known as Environmental footprint.

Explanation:

The environmental footprint describes the effect of human activities on nature, the demand and supply.

For example, the consumption of natural resources and its replenishment is measured. The measurement of human demand on nature is known as Environmental footprint.

4 0
3 years ago
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min
Lubov Fominskaja [6]

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

6 0
4 years ago
The SI unit of measurement for mass is the
olasank [31]

Answer:

m/s is answer for your questions

8 0
3 years ago
in mammal the weight of the heart approximately 0.5% total body weight write linear model that gives the heart weight in terms o
maks197457 [2]

Let the total weight of the body be = x

Let the weight of the heart of the mammals be = y

Now the given percentage of 0.5 %, we will convert it into decimal form,

so this is equal to 0.005 in decimal form,


so the linear equation that gives the heart weight in terms of body weight will be,

y = 0.005x


7 0
4 years ago
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