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expeople1 [14]
3 years ago
14

Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be tre

ated as particles and are fixed with a certain separation. (a) For what value of q/Q will the electrostatic force between the two spheres be maximized? What are the (b) smaller and (c) larger values of q/Q that give a force magnitude that is 75% of that maximum?
Physics
1 answer:
forsale [732]3 years ago
7 0

Answer:

2. Smaller value of q = 1/4Q

3. Larger value of q = 3/4Q

Explanation:

1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.

2. The smaller value is

F = 75% = 75/100

= 3/4 * Q²/16piEod² ---3

When we equate 1 and 3

We get 3Q²/16 = Qq - q² from here we cross multiply to get

3Q² = 16(Qq-q²)

3Q² = 16Qq-16q²

16q² - 16Qq + 3Q² = 0

When solve this out using the quadratic equation formula, we have:

Q/2 +- 2Q/8

We can get the smaller value of q as

Q/2-2Q/8

Solve using LCM we get

2Q/8 = 1/4Q = Q/4

C. The larger value of q

Q/2+2Q/8

= 6Q/8

= 3Q/4

Please use the attachment it will guide you to understand this better.

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(a). forms.

Explanation:

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max2010maxim [7]

Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

Explanation:

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ΔS al ≥ ∫dQ/T

if the heat transfer is carried out reversibly

ΔS al =∫dQ/T  

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ΔS surr ≥ -∫dQ/T = -ΔS al → ΔS surr ≥ -ΔS al = - (-1238 J/K) = 1238 J/K

the total entropy change will be

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A motorcycle, which has an initial linear speed of 9.7 m/s, decelerates to a speed of 4.0 m/s in 4.4 s. Each wheel has a radius
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Hi there!

We can begin by solving for the linear acceleration as we are given sufficient values to do so.

We can use the following equation:

vf = vi + at

Plug in given values:

4 = 9.7 + 4.4a

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We can use the following equation to convert from linear to angular acceleration:

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Now, we can find the angular displacement using the following:

θ = ωit + 1/2αt²

We must convert the initial velocity of the tire (9.7 m/s) to angular velocity:

v = ωr

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