Question

How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential difference is 15 kv?

Answer 1

Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV

The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.

In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.

E = V/d

E = Electric field strength

d = distance between the plates

V = potential difference

Electric field strength = 4 kV/m

Potential difference  =  15 kV

d = V / E =  15 kV / 4 kV/m

  = 3.75 m

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