Why do underwater objects appear distorted when you see them from above?

Physics

2 answers:

steposvetlana [31]3 years ago

4 0

REfraction of the rays coming from the object through the water and then being refracted into the air

WITCHER [35]3 years ago

4 0

The correct answer to the question is : Refraction.

EXPLANATION:

Before going to answer this question, first we have to understand refraction.

Refraction is the optical phenomenon in which light rays are bent at the interface of the two media due to their optical density difference.

When light comes from optical rarer medium to optical denser medium, the rays are bent towards the normal at the point of incidence.

Similarly light rays bend away from the normal when they pass from optical denser medium to optical rarer medium.

As per the questions, the object is present inside the water. The water is optically denser as compared to air. Hence, the light coming from the object is bent at the air-water interface due to refraction of light. That's why the object is appeared to be bent.

Hence, the correct answer is refraction.

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A 190 g rock at 20°C is completely immersed in 600 g of water at 80°C. Which one of the following statements is true right after

Umnica [9.8K]

Rock is completely immersed in hot water. By the second law of thermodynamics, thermal energy or heat is transferred from substance with higher temperature to substance with lower temperature until they come to thermal equilibrium i.e. both at same temperature.

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8 0

2 years ago

The starships of the Solar Federation are marked with the symbol of the Federation, a circle, whereas starships of the Denebian

Llana [10]

Complete question

The complete question is shown on the first uploaded image

Answer:

The velocity is $v = c* \sqrt{1 - \frac{1}{n^2} }$

Explanation:

From the question we are told that

a = nb

The length of the minor axis of the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the Empire's symbol, (an ellipse)

Now this length seen by the observer can be mathematically represented as

$h = t \sqrt{1 - \frac{v^2}{c^2} }$

Here t is the actual length of the major axis of of the Empire's symbol, (an ellipse)

So t = a = nb

and b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the Empire's symbol, (an ellipse)

i.e h = b

$b = nb [\sqrt{1 - \frac{v^2}{c^2} } ]$