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3 years ago

Which of the following are known to exist on the moon? select all that apply.

Physics

2 answers:

denis-greek [22]3 years ago

3 0

B. ice and d basalt............

katrin [286]3 years ago

3 0

Answer:

Ice and Basalt.

B. and D.

Explanation:

In 2018, it was confirmed by NASA that water ice exists on the surface of the moon.

In 1972, lunar basalt was picked by astronauts Eugene Cernan and Harrison Schmitt who were on the Apollo 17 mission.

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Which of the following statements concerning moral development is not true?

Goshia [24]

Answer:

C- what is determined as right or wrong is universally defined and agreed upon.

Explanation:

Correct on edge

6 0

3 years ago

Metals in group 1 on the periodic table most commonly form which type of ion

givi [52]

Answer:

Group 1 - the alkali metals. The Group 1 elements in the periodic table are known as the alkali metals.

Explanation:

7 0

3 years ago

Bats are extremely adept at catching insects in midair. If a 81.5-g bat flying in one direction at 7.21 m/s catches a 8.11-g ins

aivan3 [116]

You can look that up on google

7 0

3 years ago

A soccer player kicks a soccer ball initially at rest setting it in motion at a velocity of 30 m/s. If the ball has a mass of 0.

Alchen [17]

Answer:

F= 600 N

Explanation:

Given that

Initial velocity ,u= 0 m/s

Final velocity ,v= 30 m/s

mass ,m = 0.5 kg

time ,t= 0.025 s

The change in the linear momentum is given as

ΔP= m (v - u)

ΔP= 0.5 ( 30 - 0 ) kg.m/s

ΔP= 15 kg.m/s

We know that from second law of Newtons

$F=\dfrac{dP}{dt}$

$F=\dfrac{\Delta P}{t}$

Now by putting the values

$F=\dfrac{15}{0.025}\ N$

F= 600 N

5 0

3 years ago

Please show steps as to how to solve this problem <br> Thank you!

bezimeni [28]

Explanation:

Let x = distance of $F_1$ from the fulcrum and let's assume that the counterclockwise direction is positive. In order to attain equilibrium, the net torque $\tau_{net}$ about the fulcrum is zero:

$\tau_{net} = -F_1x + F_2d_2 = 0$

$-m_1gx + m_2gd_2 = 0$

$m_1x = m_2d_2$

Solving for <em>x</em>,

$x = \dfrac{m_2}{m_1}d_2$

$\:\:\:\:=\left(\dfrac{105.7\:\text{g}}{65.7\:\text{g}} \right)(13.8\:\text{cm}) = 22.2\:\text{cm}$

4 0

3 years ago