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2 years ago

Which of the following are known to exist on the moon? select all that apply.

Physics

2 answers:

denis-greek [22]2 years ago

3 0

B. ice and d basalt............

katrin [286]2 years ago

3 0

Answer:

Ice and Basalt.

B. and D.

Explanation:

In 2018, it was confirmed by NASA that water ice exists on the surface of the moon.

In 1972, lunar basalt was picked by astronauts Eugene Cernan and Harrison Schmitt who were on the Apollo 17 mission.

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A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i

Lunna [17]

Idk sorry maybe try @amyletbe

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3 years ago

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What did copernicus say about the motion of the sun?.

eimsori [14]

the sun was stationary in the center of the universe and the earth revolved around it....

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2 years ago

A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and

victus00 [196]

Answer:

a) $t=195.948N.m$

b) $\phi=13.6 \textdegree$

Explanation:

From the question we are told that:

Density $\rho=1.225kg/m^2$

Velocity of wind $v=14m/s$

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient $\mu=2.05$

Generally the equation for Force is mathematically given by

$F=\frac{1}{2}\muA\rhov^2$

$F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2$

$F=163.29$

Therefore Torque

$t=F*r*sin\theta$

$t=163.29*1.2*sin90$

$t=195.948N.m$

Generally the equation for torque due to weight is mathematically given by

$t=d*Mg*sin90$

Where

$d=sin \phi$

Therefore

$t=sin \phi*Mg*sin90$

$195.948=833sin \phi$

$\phi=sin^{-1}\frac{195.948}{833}$

$\phi=13.6 \textdegree$

5 0

2 years ago

Suppose an endothermic reaction has a positive change in entropy greater than the heat absorbed. What can be said about the spon

pentagon [3]

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8 0

3 years ago

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The isomerization of cyclopropane to form propene is a first-order reaction. At 760 K, 85% of a sample of cyclopropane changes t

Nataliya [291]

Answer:

so rate constant is 4.00 x 10^-4 $s^{-1}$

Explanation:

Given data

first-order reactions

85% of a sample

changes to propene t = 79.0 min

to find out

rate constant

solution

we know that

first order reaction are

ln [A]/[A]0 = -kt

here [A]0 = 1 and (85%) = 0.85 has change to propene

so that [A] = 1 - 0.85 = 0.15.

that why

[A] / [A]0= 0.15 / 1

[A] / [A]0 = 0.15

here t = (79) × (60s/min) = 4740 s

k = - {ln[A]/[A]0} / t

k = -ln 0.15 / 4740

k = 4.00 x 10^-4 $s^{-1}$

so rate constant is 4.00 x 10^-4 $s^{-1}$

3 0

2 years ago