it can be said that the speed of the east wind is
v=0.3608m/s
From the question we are told
A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).
After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,
- what is the speed of the east wind?.
<h3> the speed of the east wind</h3>
Generally the equation for the distance is mathematically given as
BA=3000sin60
BA=2598.07m
Therefore
the speed of the east wind
v=0.3608
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Two. The both have a plasma membrane and cytoplasm.
Answer:
(a) Acceleration of the bag will be a=16.214m/sec^2
(B) Weight of the bag will be 137.2 N
Explanation:
We have given mass of the bag m = 14 kg
Force with which bag is lifted = 227 N
(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration
So 
(b) Acceleration due to gravity 
We know that weight is given by W = mg , here m is mass and g is acceleration due to gravity
So weight 
So weight of the bag will be 137.2 N
Answer:
1.190390345 degrees.
Explanation:
As stated in the problem that the angle between the two curves is also the angle between slopes of the two cures at the point of intersection, which is 1 (when we set two equation equal and solve for x).
We know, if you don't you could verify it for yourself and it will be a nice mathematical exercise for you, that when there are two lines with slopes 
and 
then the angle between them and their two slopes has following relationship.
where 
is angle between the two lines.
As it is clear that we can easily get the angle between the two curves if we know slopes at that point, which you will see in second is very straight forward to calculate.
Slopes are simply derivatives evaluated at the point of intersection and the two derivatives are 
16x and 
, substituting x =1 we get, 
and 
.
Now put and in this relationship, rearrange and solve for angle, it will come out to be
= 1.190390345 degrees.
that is our angle that we want to know between the two cures at the point of their intersection.
Answer:
1.5 m
Explanation:
a = v/t
a = 2/1,5 = 4/3
x = 1/2 a t² + vt + x
x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m
