1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
boyakko [2]
2 years ago
14

A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field

created by the positive test charge also specify the direction of the electric field with respect to the force

Physics
1 answer:
Sophie [7]2 years ago
8 0

Explanation:

direction of electric field is same as that of force experienced by the test charge

You might be interested in
Which of the following changes occurs during nuclear fission?
coldgirl [10]

Answer:

The parent nucleus splits into lighter daughter elements

Explanation:

Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles

8 0
3 years ago
Measuring the diameter of a specific object might include which pair of SI units
VLD [36.1K]

Well, the diameter of a circle is simply a length, so your measurement will have units of length.  We just have to find an answer that has only units of length.

A).  gram, second . . . mass and time.  That can't be it.

B).  kilogram, ampere . . . mass and current.  That can't be it.

C).  centimeter, meter . . . both lengths. This one is looking good.

D).  candela, mole . . . light intensity and some chemical thing. That can't be it.

So it can't be anything else on this list but <em>C</em> .

8 0
3 years ago
A solid ball of radius rb has a uniform charge density rho.
Oksana_A [137]

Note: question B is incomplete.

Complete Question

A solid ball of radius rb has a uniform charge density ρ.

a.  What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball?  Express your answer in terms of ρ, rb, r, and ϵ0.

b.   What is the magnitude of the electric field E(r) at a distance r<rb from the center of the ball?  Express your answer in terms of ρ, r, rb, and ϵ0.

c.   Let E(r) represent the electric field due to the charged ball throughout all of space. Which of the following statements about the electric field are true?

1. E(0) = 0.

2. E(rb) = 0

3. lim E(r) = 0.

4. The maximum electric field occurs when r = 0.

5. The maximum electric field occurs when r = rb.

6. The maximum electric field occurs as r to infinity.

Answer:

a) the magnitude of E(r)= ρr³/3 ε₀r²

b) the magnitude at distance r from the centre E(r)= ρr/3 ε ₀ ( if r<rb)

c) statements 1(E(0) = 0), 3(E(0) = 0) and 5(The maximum electric field occurs when r = rb.) are true

Explanation:

given

charge density = ρ ,  ε

Volume of sphere , V = (⁴/₃)πr³

a) charge density = charge/volume

ρ = q ÷ V

make charge the subject of the formula

∴q = ρ × V=  ρ× (⁴/₃)πr³

where r³ = rb³(at distance rb³)

recall

E= q/4πε₀r²

E=  ρ × (⁴/₃)πrb³/4πε₀r²

∴E(r)= ρrb³/3 ε ₀r²

(b)  The Gaussian surface is inside the ball, therefore, surface only encloses a portion of ball's charge .

The net charge enclosed by the Gaussian surface is different to the of net charge enclosed in (a)

Recall

E= q/4πε₀r²

V= (⁴/₃)πr³

E=  ρ × (⁴/₃)πr³/4πε₀r²

∴E(r)= ρr/3 ε₀

(c)  E(0)= 0

limr-----∝

E(r)= 0

The maximum electric field occurs when r=rb.

4 0
3 years ago
How many significant digits are in the number 204.0920<br>​
monitta

Answer:

Seven

Explanation:

The rules for significant digits are:

  • Non-zero digits are always significant.
  • Zeros between significant digits are also significant.
  • Trailing zeros are significant only after a decimal point.

Here, the 2, 4, 9, and 2 are significant because they are non-zero digits.

The first two 0s are significant because they are between significant digits.

The last 0 is significant because it is a trailing zero after a decimal point.

Therefore, all seven digits are significant.

3 0
3 years ago
Read 2 more answers
A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hea
DENIUS [597]

Answer:

v = 33.66 m/s

Explanation:

Let hockey puck is moving at constant speed v

so here we have

d = vt

so time taken by the puck to strike the wall is given as

t = \frac{58.2}{v}

now time taken by sound to come back at the position of shooter is given as

t_2 = \frac{58.2}{340}

t_2 = 0.17s

so we know that total time is 1.9 s

1.9 = t + t_2

1.9 = t + 0.17

1.9 - 0.17 = t

t = 1.73 s

now we have

1.73 = \frac{58.2}{v}

v = 33.66 m/s

7 0
3 years ago
Other questions:
  • A single slit of width 0.50 mm is illuminated with light of wavelength 500 nm, and a screen is placed 120 cm in front of the sli
    12·1 answer
  • You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 15.0 m above the ground, it is tr
    7·1 answer
  • A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd
    13·2 answers
  • A spring-loaded toy gun is used to launch a 12.0-g plastic ball. The spring which has a spring constant of 15.0 N/m is compresse
    6·1 answer
  • Would you expect the density of graphite and diamond to be the same
    7·1 answer
  • What is A rounded to the nearest tenth?
    12·1 answer
  • Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)
    14·2 answers
  • A rock on earth has a weight of 135 Newtons. What is its mass?
    8·1 answer
  • Does bouncing or sticking produce more impulse?
    12·2 answers
  • - Light bulbs can be used to indicate current flow in a circuit. The brightness of a bulb is proportional to the amount of curre
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!