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padilas [110]
2 years ago
10

Question 1

Physics
1 answer:
svetlana [45]2 years ago
7 0

300

Explanation:

100 x 3 =300 simple and easy

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A room that has an average ambient sound pressure level of 62 dBA and a maximum sound pressure level lasting more than a minute
cupoosta [38]

Answer:

Explanation:

A fire alarm notification appliance is an active fire protection component of a fire alarm system. The primary function of the notification appliance is to alert persons at risk.

If want the audible public mode signal to be hear clearly then, we need to have a sound level that is at least 15dB above the average ambient sound level or 5dB above the maximum sound level of at least 1minute

In this case the,

The average ambient sound level is 62dB,

And the maximum sound level is 68dB

Then, the public mode signal should be at least

1. 62dB+ 15dB=77dB

Or

2. 68dB +5dB =73dB.

Then the public mode signal hearing must be at least 77dB.

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4 years ago
Why do you think that some asteroids tumble end over end through space while other asteroids rotate around their axis?
Scilla [17]
Asteroids do this because of Newton's Third Law. When a asteroid hits something, it will keep on moving (spinning) until it hits something else. 
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3 years ago
What is meant by the term valence electrons
3241004551 [841]
Electrons on the outermost shell/energy level
3 0
3 years ago
Who first proposed that each layer of rock represented a specific interval of geologic time?
RoseWind [281]

Hutton, a Scottish geologist.

4 0
3 years ago
A dipole is located at the origin, with charges +3 nC and -3 nCseparated by 4 μm. Consider a spherical Gaussian surfacecentered
kirza4 [7]

Answer:

Explanation:

a )  

The Gaussian surface must  have contained both the charges like +3 nC and - 3 nC , total charges being zero . According the Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times the total charge contained inside the closed surface .

Since total charge inside is zero , total flux will be 1 /  ε₀ x 0 = 0

b )

In this case the Gaussian surface is so small that it contains only the charge

+ 3 nC .

So electric flux over the Gaussian surface

= (  1 /  ε₀ ) x 3 x 10⁻⁹

= (1 / 8.85 x 10⁻¹² ) x 3 x 10⁻⁹

= 3 x 10³ / 8.85

= 339 weber.  

=

6 0
3 years ago
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