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rodikova [14]
3 years ago
11

What is the value of x in the equation 8x - 2y = 48, when y = 4?

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:

x = 7

Step-by-step explanation:

8x - 2y = 48

Let y=4

8x - 2(4) = 48

8x -8 = 48

Add 8 to each side

8x -8+8 = 48+8

8x = 56

8x/8 = 56/8

x = 7

spin [16.1K]3 years ago
5 0
8x-2(4)=48 Then, 8x-8=48 Then, 8x=56 Then X=7


The value of x in the equation is 7.
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14,2,7,3,9 =10 I need help
Misha Larkins [42]

Answer: 7+3 =10

Step-by-step explanation: Those were the only two numbers added or subtracted together that I found made 10. I hope this helps :).

7 0
2 years ago
Jill makes purses and backpacks. To make each purse,she uses 1foot less than half the amount of fabric she uses to make a backpa
nikklg [1K]

Answer:

Step-by-step explanation:

Jill makes purses and backpacks.

Let x represent the number of foot of fabric required to make a purse.

Let y represent the number of foot of fabric required to make a backpack.

To make each purse,she uses 1 foot less than half the amount of fabric she uses to make a backpack. This means that

x = (y/2) - 1

Therefore, the amount of fabric that Jill needs to make backpack will be

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The number of feet of fabric that she will use to make a purse is

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4 0
3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

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Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

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Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

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2 years ago
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puteri [66]
1st. is definitely 150.
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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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