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kenny6666 [7]
2 years ago
10

What is 20 times 200000000

Chemistry
1 answer:
iren [92.7K]2 years ago
4 0

Answer: 4000000000

because 20X200000000=4000000000

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Write a balanced nuclear equation for the β emission of the following isotopes
andrezito [222]

The balanced nuclear equation for the β emission of the following isotopes is seen below:

92                 92                0

Sr            ⇒ Y         +   e

38                  39             -1

<h3>What is Beta emission?</h3>

This is also known as beta decay in which a beta ray is emitted from an atomic nucleus.

The element formed during the beta emission of strontium is referred to as Yttrium.

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6 0
2 years ago
Select all of the answers that apply.
saveliy_v [14]
A meteorologist predicts fog in the morning over lakes and river bottoms because of the atmospheric conditions and their interactions with the <span>hydrosphere. The hydrosphere is the region on the Earth's surface where the total water on the planet is found. The hydrosphere can be in the form of liquid, vapor, or ice.</span>
5 0
2 years ago
1. A mixture contains 8.00 g each of O2, CO2, and SO2 at STP. Calculate the volume of this mixture. Which of the gases would exe
Gekata [30.6K]

Answer:

Explanation:

mole of O₂ = \frac{8}{32}

= .25 moles

mole of CO₂

= \frac{8}{44}

= .1818 moles

moles of SO₂

\frac{8}{64}

= .125 moles

Total moles of gas

= .5568 moles.

total volume of gas mixture

= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)

= 12.47 liter.

gas will exert partial pressure according to their mole fraction

gas having greatest no of moles in the total mole will have greatest mole fraction so

O₂ will have greatest partial pressure.

7 0
3 years ago
What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

7 0
3 years ago
May you please help if you don’t know scroll it you’re 100% thank you
grandymaker [24]

Answer: rise earlier and set later

Explanation: just trust me hope this helps

5 0
3 years ago
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