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FrozenT [24]
3 years ago
14

Determine the molality of an aqueous solution that is 16.5 percent urea by mass

Chemistry
1 answer:
yarga [219]3 years ago
7 0

Take a hypothetical sample of exactly 100 grams of the solution.  

(16g urea) / (60.06 g urea/mol) = 0.2664 mol urea  

((100 g total) - (16g urea)) = 84.0 g H2O = 0.0840 kg H2O  

(0.2664  mol) /0.0840  (kg) = 3.17143mol/kg = 3.18m urea


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