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FrozenT [24]
3 years ago
14

Determine the molality of an aqueous solution that is 16.5 percent urea by mass

Chemistry
1 answer:
yarga [219]3 years ago
7 0

Take a hypothetical sample of exactly 100 grams of the solution.  

(16g urea) / (60.06 g urea/mol) = 0.2664 mol urea  

((100 g total) - (16g urea)) = 84.0 g H2O = 0.0840 kg H2O  

(0.2664  mol) /0.0840  (kg) = 3.17143mol/kg = 3.18m urea


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Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
Water is produced from the reaction of hydrogen and oxygen gas, according to the equation below. What is the excess reactant in
liq [111]

Explanation:

Mole ratio of Oxygen to Hydrogen gas = 1 : 2.

If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.

However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)

3 0
3 years ago
Drinking water may contain a low concentration of lead ion (Pb2 ) due to corrosion of old lead pipes. The EPA has determined tha
Lynna [10]

Answer:

3.861x10⁻⁹ mol Pb⁺²

Explanation:

We can <u>define ppm as mg of Pb²⁺ per liter of water</u>.

We<u> calculate the mass of lead ion in 100 mL of water</u>:

  • 100.0 mL ⇒ 100.0 / 1000 = 0.100 L
  • 0.100 L * 0.0080 ppm = 8x10⁻⁴ mg Pb⁺²

Now we <u>convert mass of lead to moles</u>, using its molar mass:

  • 8x10⁻⁴ mg ⇒ 8x10⁻⁴ / 1000 = 8x10⁻⁷ g
  • 8x10⁻⁷ g Pb²⁺ ÷ 207.2 g/mol = 3.861x10⁻⁹ mol Pb⁺²
4 0
3 years ago
How many grams are in 0.35 moles of C2H4? please show dimensional analysis
fredd [130]

Answer:

9.8g

Explanation:

Using periodic table find molar mass of C and H:

C=12.01g/mol

H=1.008g/mol

Molar mass of C2H4=(12.01)2+(1.008)4=28.03g/mol

Using molar mass times moles of the chemical to find the mass in 0.35 moles of c2h4:

28.03 x 0.35=9.8grams

5 0
3 years ago
Which of the following are characteristics of transition metals?
Kipish [7]

Answer:

High melting point,High density,Nonreactive

Explanation:

The following are the Properties of transition elements:

They have large charge/radius ratio. They are harder and they have high densities;.They have high melting and boiling points.They form compounds which are paramagnetic. They show variable oxidation states. They form colored ions and compounds. Compounds are formed with profound catalytic activity. Stable complexes are formed by them.

When Comparing with the alkali metals present in group 1 and the alkaline Earth metals that are present in group 2, the transition metals are considered to be much less reactive. They do not react fast with water or oxygen, which contributes to their resistance to corrosion.

8 0
3 years ago
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