Solve the following quadratic equation: the following quadratic equation: 2x2 - 52 + 2 = 0

Mathematics

1 answer:

irina [24]3 years ago

6 0

Answer:

Step-by-step explanation:

$2x^2 - 52 + 2 = 0\\\\2x^2-50=0\\\\x^2-25=0\\\\x^2=25\\\\x=5\qquad\vee\quad\ x=-5$

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Vesnalui [34]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

100 POINTS! I REALLY NEED TO GET THIS CORRECT! Factor the quadratic trinomial.

Assoli18 [71]

The factors of the equation $x^2-3x-18$ are $(x-6)(x+3)$

Step-by-step explanation:

We need to factor the quadratic trinomial. $x^2-3x-18$

We will do factorization by braking the middle term such that adding those number we get middle term (-3x) and multiplying those numbers we get (-18x^2)

Solving:

$x^2-3x-18\\=x^2-6x+3x-18\\=x(x-6)+3(x-6)\\=(x-6)(x+3)$

So, the factors of the equation $x^2-3x-18$ are $(x-6)(x+3)$

Keywords: Finding Factors of Quadratic Equation

Learn more about Finding Factors of Quadratic Equation at:

#learnwithBrainly

8 0

4 years ago

Hi please i nedd help with these questions .

Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

$\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}$

division sign means that we flip the fraction

$\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}$

now we can multiply all the constants together and all variables

$m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}$