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3 years ago

Describe how radio telescopes function.

1 answer:

7 0

A radio telescope is simply a telescope that is designed to receive radio waves from space. In its simplest form it has three components:

1. One or more antennas to collect the incoming radio waves. Most antennas are parabolic dishes that reflect the radio waves to a receiver, in the same way as a curved mirror can focus visible light to a point.

2. A receiver and amplifier to boost the very weak radio signal to a measurable level. These days the amplifiers are extremely sensitive and are normally cooled to very low temperatures to minimise interference due to the noise generated by the movement of the atoms in the metal (called thermal noise).

3. A recorder to keep a record of the signal. Most radio telescopes nowadays record directly to some form of computer memory disk as astronomers use sophisticated software to process and analyse the data.

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At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan

Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time $t_1$ , the acceleration vector has direction $\theta_1$ such that

$\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ$

which indicates the particle is situated at a point on the lower left half of the circle, while at time $t_2$ the acceleration has direction $\theta_2$ such that

$\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ$

which indicates the particle lies on the upper left half of the circle.

Notice that $\theta_1-\theta_2=90^\circ$ . That is, the measure of the major arc between the particle's positions at $t_1$ and $t_2$ is 270 degrees, which means that $t_2-t_1$ is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

$\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}$

where $R$ is the radius of the circle and $T$ is the period. We have

$t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s$

and the magnitude of the particle's acceleration toward the center of the circle is

$\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}$

So we find that the path has a radius $R$ of

$7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}$

8 0

3 years ago

Can gravity be considered a force? Why or Why not?

vivado [14]

Yes, because gravity will pull objects down to Earth.

3 0

3 years ago

Read 2 more answers

Which physical property of iron is being tested in the picture

Molodets [167]

Answer:

Electrical Conductivity

Explanation:

it was on test

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3 years ago

List two of the tangible and/or intangible ways in which state governments improve society

pshichka [43]

<span>Two tangible ways in which state governments improve society would be through the construction of public facilities like libraries and roads, and an intangible example would be through welfare programs. other wise i suck but this is my best answer hope it helps enjoy

</span>

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3 years ago

Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in

labwork [276]

Kinetic Energy

How to calculate

Kinetic energy is given by K.E.

$\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2$

Where

m is denoted to mass
v is denoted to velocity

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3 years ago