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sasho [114]
3 years ago
6

Describe how radio telescopes function.

Physics
1 answer:
FrozenT [24]3 years ago
7 0

A radio telescope is simply a telescope that is designed to receive radio waves from space. In its simplest form it has three components:

1. One or more antennas to collect the incoming radio waves. Most antennas are parabolic dishes that reflect the radio waves to a receiver, in the same way as a curved mirror can focus visible light to a point.

2. A receiver and amplifier to boost the very weak radio signal to a measurable level. These days the amplifiers are extremely sensitive and are normally cooled to very low temperatures to minimise interference due to the noise generated by the movement of the atoms in the metal (called thermal noise).

3. A recorder to keep a record of the signal. Most radio telescopes nowadays record directly to some form of computer memory disk as astronomers use sophisticated software to process and analyse the data.

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ANEK [815]

Answer:

It states a fact about how nature works.

It often changes over time with new experiments and technology.

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- With the device starting from a still position (0 m/s), you drop it, allowing gravity to accelerate it towards the ground at 9
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3 0
3 years ago
The center of mass of a 0.3 kg (non-uniform) meter stick is located at its 46-cm mark. What is the magnitude of the torque (in N
Sati [7]

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15cm

Explanation:

7 0
3 years ago
Calculate the focal length of a lens needed by a woman whose near point is 50cm from her eyes, assuming the least distance of di
son4ous [18]

The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

To find the answer, we have to know about the focal length of correcting lens.

<h3>How to find the focal length of correcting lens?</h3>
  • If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,

                           f=\frac{XD}{X-D}

  • It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,

                       f=\frac{50*25}{50-25} =50cm.

Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

Learn more about the focal length here:

brainly.com/question/27915592

#SPJ9

4 0
1 year ago
If the speed of light in a medium is 2 x 10^8 m/s, the medium's index of refraction is?
steposvetlana [31]
Speed of light in the air is 3 x 10^8
so index of refractions would be speed of light divided by speed in the medium
3/2 = 1.5

Answer: n=1.5

by the way it is glass :) 
6 0
3 years ago
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