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Travka [436]
3 years ago
5

By what factor will the acceleration of an object change its mass stays constant but the force acting on it triples

Physics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

lacceleration is given by

a=F/m

With force acting on the object remained constant ,the acceleration is inversly proportional to mass of the object i.e with increase in mass =>acceleration decreases and with decrease in mass => acceleration increases.

a)

acceleration decreases

b)

acceleration increase

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Ferns that eject spores generally do so in pairs, with two spores flying off in opposite directions. The structure from which th
Furkat [3]

Answer:

It cancels recoil.

Explanation:

For each action there is an equal an opposite reaction.

The principle of conservation of momentum tell us that if a single spore were ejected the fern would suffer a recoil from it. This recoil would take energy and speed from the spore. But if they are ejected in pairs the recoil is canceled and all the energy is transferred to the spores resulting in higher speeds.

5 0
4 years ago
I needed ASAP!!!
11111nata11111 [884]
They are moving in opposite direction, cant find out anything else because not enough informations is provided, like time .
7 0
3 years ago
Need definitions for these please
77julia77 [94]
Ammonia=a colorless gas with a characteristic pungent smell. It dissolves in water to give a strongly alkaline solution.

Inert=lacking the ability or strength to move.

Nitrates=a salt or ester of nitric acid, containing the anion NO3− or the group —NO3.

Limiting nutrient S=Nitrogen and phosphorus are frequently called “limiting nutrients.” This means that at any given time, one or the other of these nutrients may be the hardest nutrient for a plant to acquire and therefore be the only nutrient that is limiting the plant's growth.
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Eutrophication=excessive richness of nutrients in a lake or other body of water, frequently due to runoff from the land, which causes a dense growth of plant life and death of animal life from lack of oxygen.
 Nitrification=Nitrification is the biological oxidation of ammonia or ammonium to nitrite followed by the oxidation of the nitrite to nitrate. The transformation of ammonia to nitrite is usually the rate limiting step of nitrification. Nitrification is an important step in the nitrogen cycle in soil.

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5 0
4 years ago
Evan drew a diagram to illustrate radiation.
Vesna [10]

The correct answer is:

D. Electromagnetic waves.

The arrows represent electromagnetic waves.

|Huntrw6|

8 0
3 years ago
A piston having 7.23 g of steam at 110°C increases its temperature by 35°C. At the same time it expands from a volume of 2.00 L
My name is Ann [436]

Answer : The value of q,w,\Delta U\text{ and }\Delta U is 505 J, -599 J, -94 J and -693 J respectively.

Explanation : Given,

Mass of steam = 7.23 g

Initial temperature = 110^oC

Final temperature = (110+35)^oC=145^oC

Initial volume = 2 L

Final volume = 8 L

External pressure = 0.985 bar

Heat capacity of steam = 1.996 J/g.K

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta U=q+w

First we have to calculate the heat absorbed by the system.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat absorbed by the system = ?

m = mass of steam = 7.23 g

C_p = heat capacity of steam = 1.966J/g.K

T_1 = initial temperature  = 110^oC=273+110=383K

T_2 = final temperature  = 145^oC=273+145=418K

Now put all the given value in the above formula, we get:

Q=7.23g\times 1.966J/g.K\times (418-383)K

Q=505J

Now we have to calculate the work done.

Formula used :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done  = ?

p_{ext} = external pressure = 0.985 bar = 0.985 atm   (1 bar = 1 atm)

V_1 = initial volume of gas = 2.00 L

V_2 = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(0.985atm)\times (8.00-2.00)L

w=-5.91L.atm=-5.91\times 101.3J=-599J

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the change in internal energy of the system.

\Delta U=q+w

\Delta U=505J+(-599J)

\Delta U=-94J

Now we have to calculate the change in enthalpy of the system.

Formula used :

\Delta H=\Delta U+P\Delta V

\Delta H=\Delta U+w

\Delta H=(-94J)+(-599J)

\Delta H=-693J

Therefore, the value of q,w,\Delta U\text{ and }\Delta U is 505 J, -599 J, -94 J and -693 J respectively.

4 0
4 years ago
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