1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
3 years ago
10

Find the electric field at a point midway between two charges of 30.0×10 power -9 and 60.0×10 power -9 separated by a distance o

f 30.0 cm
Physics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

The electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C

Explanation:

Let the midpoint of the two charges be considered as the origin, and charge A = 30.0 * 10⁻⁹ C be moving in the +x- axis and the charge B = 60.0 * 10⁻⁹ C be moving in the -x-axis.

Electric field, E = kQ/r² where k is a constant = 9.0 * 10⁹  N.m²/C², Q = quantity of charge, r = distance of separation

In the given question,r = 30.0 cm = 0.03 m; the midway point between A and B = 0.03/2 = 0.015 m

Electric field due to charge A

Ea = +(9.0 * 10⁹  N.m²/C² * 30.0 * 10⁻⁹ ) / ( 0.015 m)²

Ea =  +1.8 * 10⁴ N/C

Electric field due to charge B

Eb = -(9.0 * 10⁹  N.m²/C² * 60.0 * 10⁻⁹ ) / ( 0.015 m)²

Eb =  -3.6 * 10⁴ N/C

The resultant electric field E = Ea + Eb

E = (+1.8 * 10⁴  +  -3.6 * 10⁴) N/C

E = -1.8 * 10⁴ N/C

Therefore, the electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C

You might be interested in
1 point
alexandr1967 [171]

Answer:

length

<em>Your</em><em> </em><em>well</em><em> </em><em>wisher</em><em> </em><em>:-)</em>

4 0
2 years ago
The bending of waves such as sound waves, light waves, and waves in water, around obstacles or the edges of openings is called.
kolezko [41]

Answer:

Diffraction

Explanation:

Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.

4 0
10 months ago
1. The hockey puck is given an initial speed of 20.0m/s on a frozen pond. The
andreyandreev [35.5K]
Yurooo iwhvrn u w. N f c
5 0
3 years ago
Read 2 more answers
Pls help
belka [17]

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these  value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

4 0
2 years ago
Could I please get some help on this question I don’t understand .
Oksana_A [137]

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 8 m

Final velocity (v) at 8 m above the lowest point =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 8)

v² = 0 + 156.8

v² = 156.8

Take the square root of both side

v = √156.8

v = 12.5 m/s

Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.

5 0
3 years ago
Other questions:
  • In this problem, you will answer several questions that will help you better understand the moment of inertia, its properties, a
    9·1 answer
  • After an earthquake, which type of seismic wave arrives last at a seismometer?
    6·1 answer
  • A magnetic B field of strength 0.4 T is perpendicular to a loop with an area of 1 m2. If the area of the loop is reduced to zero
    11·1 answer
  • The total magnification of a specimen being viewed with a 10X ocular lens and a 40X objective lens is _____.
    10·1 answer
  • PART ONE
    7·1 answer
  • If an object is not accelerating, it can exist in what 2 other states of motion?
    13·1 answer
  • Dynamo converts the
    7·2 answers
  • Motion is the act of ___<br> the options are movement, feeling, chemical engergy and sleep
    12·2 answers
  • Please view attached images. The first one is #2 and the second one is #1.
    13·1 answer
  • How to find velocity of center of mass before and after the collision
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!