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3 years ago

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- With the device starting from a still position (0 m/s), you drop it, allowing gravity to accelerate it towards the ground at 9

.8 m/s2. Assuming it takes 1.5 seconds for the device to hit the ground, what is it’s velocity? [V = a*t]

1 answer:

IrinaVladis [17]3 years ago

3 0

Starting velocity (u)=0
acceleration (a) = 9.8
time (t) = 1.5
final velocity (v) =?

v=at+u
v=9.8(1.5)+0
v=14.7m/s2

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