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Olenka [21]
3 years ago
12

HELP!!!!!!!! Which is the best example of reusing?

Chemistry
2 answers:
Vinvika [58]3 years ago
5 0

Answer:

it is A repairing a stove insted of buying a new one

Explanation:

because instead of getting rid of it your fixing it so it can be reused pls give brainliest

zhuklara [117]3 years ago
4 0

Answer:

placing a glass bottle in the recycling bin is what i think.

Explanation:

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Which list includes three forms of energy?
loris [4]
 I think the correct answer from the choices listed above is option 1. The list that includes three forms of energy would be chemical, mechanical and electromagnetic. Pressure and temperature are not energy. Hope this answers the question. Have a nice day.
5 0
3 years ago
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Which of the following would form a cation? Ne Li O I
geniusboy [140]
Li because its charge is +1.
5 0
3 years ago
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Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
A car travels 150 meters in 3.5 seconds what is its speed?
defon

Answer:

The solution is given below.

Explanation:

Speed   = Distance(m)/Time(sec.)

Distance traveled = 150 m

Time taken = 3.5 seconds

Speed of car = 150/3.5 = 42.86 m/s

So the car traveled at a speed of 42.86 m/s.

6 0
3 years ago
Select the conjugate acid-base pair(s). a) HI, I b) HCHO2, SO4^2- c) CO3^2-, HCI d) PO4^3-, HPO4^2-
Semenov [28]

Answer:

d) PO4^3-, HPO4^2-

Explanation:

Basically, an acid and a base which differs only by the presence or absence of  proton (hydrogen ion) are called a conjugate acid-base pair.

a) HI, I

This is incorrect. For the acid, HI the conjugate base is I⁻ ion.

b) HCHO2, SO4^2-

This is incorrect, there's no relationship between both entities.

c) CO3^2-, HCI

This is incorrect, there's no relationship between both entities.

d) PO4^3-, HPO4^2-

This is correct. The difference between both entities is the Hydrogen ion. This is the conjugate acid-base pair

6 0
3 years ago
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