Answer:
Explanation:
The question is incomplete. Here is the complete question.
"Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 20-V battery. Part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. In part (b), three resistors are specified. (a) Two resistors are connected in series across a 20-V battery. Let R1 = 1 Ω and R2 = 2 Ω. Rea = (b) Add a third resistor to the circuit in series. Let R1 = 1 Ω, R2 = 2 Ω, and R3 = 3 Ω"
Using ohms law formula to solve the problem
E = IRt
E is the supply voltage
I is the total current
Rt is the total equivalent resistant.
a) Given two resistances
R1 = 1ohms and R2 = 2ohms
If the resistors are Connected in series across a 20V supply voltage,
-Equivalent resistance = R1+R2
= 1ohms + 2ohms
= 3ohms
- In a series connected circuit, same current flows through the resistors.
Using the formula E = IRt
I = E/Rt
I = 20/3
I = 6.67A
The current in both resistors is 6.67A
- Different voltage flows across a series connected circuit.
Using the formula V = IR
V is the voltage across each resistor
I is the current in each resistor
For 1ohms resistor,
V = 6.67×1
V = 6.67Volts
For 2ohms resistor
V = 6.67×2
V = 13.34Volts
b) If the resistors are three
R1 = 1ohms, R2 = 2ohms R3 = 3ohms
- Total equivalent resistance = 1+2+3
= 6ohms
- Current in each resistor I = E/Rt
I = 20/6
I = 3.33A
Since the same current flows through the resistors, the current across each of them is 3.33A
- Voltage across them is calculated as shown:
V = IR
For 1ohm resistor
V = 3.33×1
V = 3.33volts
For 2ohms resistor
V = 3.33×2
V = 6.66volts
For 3ohms resistor
V = 3.33×3
V = 9.99volts
E
(9.35) = 1057.46 lumens (lm)