Answer:
710,33 g NO2
Explanation:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 used to combust the octane
= 15.44 mol O2 used to form NO2
O2 + 2NO → 2NO2
(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710,33 g NO2
24 gFeF3 x (1 mol FeF3/grams FeF3)
x (6.02x10^23 molecules FeF3/ 1 mol FeF3)
Just Calculate Molar Mass of FeF3 and plug into equation
30ml of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.750 M solution.
<h3>What is HCl?</h3>
HCl is an acid which is made up of hydrogen and chlorine gas.
By the formula of dilution
M1V1 = M2V2
where V1 = 2.50 m
M2 = 100.0
V2 = 0.750 m
M1 × 2.50 m = 100.0 × 0.750 m
M1 = 30 ml
Thus, the M1 is 30 ml option a is correct.
Learn more about HCl
brainly.com/question/3637432
Educated Guess Here!
Since Br-80 does not exist, maybe that means Br-79 or Br-81 have very unequal abundances. For example, Br-79 may have 75% abundance whereas Br-81 may have 25% abundance.
