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3 years ago

When two fluorine atoms bond together in F2, what type of covalent bond do they form?

Chemistry

2 answers:

andrew11 [14]3 years ago

5 0

Answer:

A single bond bc they overlap to share ONE pair of electrons

Explanation:

Took the test

makvit [3.9K]3 years ago

4 0

When two fluorine atoms bond together in f2 the type of covalent bond do they form is non-polar covalent bond.

Explanation

They are two type of covalent bond. that is non polar covalent bond and polar covalent bond.

Non polar covalent bond is formed when atoms share a pair of electrons with each other equally.

polar covalent bond is bond formed when atoms share a pair electrons unequally.

F2 is a non polar since it is made up of two same atoms which has the same electronegativity, therefore equal number of electrons exist in the orbital overlap.

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seraphim [82]

Answer:

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3 years ago

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The ground -state electron configuration contains 6p unpaired electrons .

yulyashka [42]

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3 years ago

How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

Afina-wow [57]

Answer : The mass of $PbSO_4$ needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of $PbCrO_4$ .

$\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole$

Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

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Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

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3 years ago

Compared to a 0.1 M aqueous solution of NaCl, a 0.8 M aqueous solution of NaCl has a

Fudgin [204]

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4 years ago

What is the empirical formula for the compound C36H72O36?

Westkost [7]

CH20
Just reduce the subscripts on all of them they’re all divisible by 36 in this case

7 0

3 years ago