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2 years ago

When two fluorine atoms bond together in F2, what type of covalent bond do they form?

Chemistry

2 answers:

andrew11 [14]2 years ago

5 0

Answer:

A single bond bc they overlap to share ONE pair of electrons

Explanation:

Took the test

makvit [3.9K]2 years ago

4 0

When two fluorine atoms bond together in f2 the type of covalent bond do they form is non-polar covalent bond.

Explanation

They are two type of covalent bond. that is non polar covalent bond and polar covalent bond.

Non polar covalent bond is formed when atoms share a pair of electrons with each other equally.

polar covalent bond is bond formed when atoms share a pair electrons unequally.

F2 is a non polar since it is made up of two same atoms which has the same electronegativity, therefore equal number of electrons exist in the orbital overlap.

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An individual has calculated her ecological footprint. What does this

Lunna [17]

Answer: C

Explanation:

The impact she has on the environment

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2 years ago

Classify the following compounds as ionic or covalent:. a.H2O. b.C6H12O6. c.CuBr2. d.KMnO4. e.C2H6. f.Fe(C2H3O2)3. . How do you

Papessa [141]

Ionic compounds are compounds composed of a metal as the cation (positive charge) and non-metals as anion (negative charge). Covalent compounds are composed of both non-metals. In this respect, a) water is covalent b) covalent c) ionic d) ionic e) covalent f) ionic.

4 0

2 years ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

4 0

2 years ago

When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation of two new nuc

user100 [1]

Answer:

$^{139}_{56}Ba$

Explanation:

The fission reaction taking place given in the question is:

$^{235}_{92}U+^{1}_{0}n\rightarrow ^{A}_{Z}Ba+^{94}_{36}Kr+3^{1}_{0}n$

The mass is conserved in the reaction.

So,

235 + 1 = A + 94 + 3×1

A = 139 g/mol

Also, number o protons remain same. So,

92 = Z + 36

Z = 56

The isotopic symbol is $^{139}_{56}Ba$

5 0

3 years ago

When potassium metal is placed in water a large amount of energy is released as potassium hydroxide and hydrogen gas are produce

Ann [662]

Explanation:

$2K(s)+2H_2O\rightarrow 2KOH(aq)+H_2(g)$

The given reaction is redox reaction but not combustion reaction.

Redox reaction : It is a chemical reaction in which oxidation and reduction occurs simultaneously.Oxidation is gaining of electrons and reduction is loosing of electrons.

$K\rightarrow K^++e^-$ oxidation

$2H^++2e^-\rightarrow H_2$ reduction

Potassium when reacts with water ,gives potassium ion in aqueous medium and combines with hydroxide ion present in water to form potassium hydroxide where as $H^+$ ions of water by gaining electrons (from potassium in water) gives hydrogen gas.

Hence , yes it is a redox reaction

Combustion reaction are the chemical reaction in which one reactant react with oxygen molecule to give heat and light.

Here in given reaction no oxygen molecule is appearing on reactant side.

Hence not a combustion reaction.

6 0

2 years ago