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inessss [21]
1 year ago
6

How many moles of NO2 form when 63.25 g N2O5 decompose? 2N2O5→ 4NO2 + 0₂

Chemistry
1 answer:
GREYUIT [131]1 year ago
7 0

Answer:

1.1713 moles

Explanation:

RFM of N2O5= (14*2)+(16*4)=108

Moles of N2O5= Mass/RFM= 63.25/108= 0.5856 moles

Mole ratio of N2O5:NO2 = 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles

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plz answer 7 & 8 because I dont get the answer... oh and you need to use the picture for the questions 7 & 8 thanks
djyliett [7]
7. An exothermic reaction
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3 years ago
A/an _______ bond allows metals to conduct electricity
Alona [7]
<span>n a metallic bond, atoms of the metal are surrounded by a constantly moving "sea of electrons." This moving sea of electrons enables the metal to conduct electricity.
Answer: Metallic</span>
7 0
3 years ago
Calculate the feed ratio of adipic acid and hexamethylene diamine that should be employed to obtain a polyamide of approximately
artcher [175]

Answer:

r= 0.9949 (For 15,000)

r=0.995 (For 19,000)

Explanation:

We know that

Molecular weight of hexamethylene diamine = 116.21 g/mol

Molecular weight of adipic acid = 146.14 g/mol

Molecular weight of water = 18.016 g/mol

As we know that when  adipic acid  and hexamethylene diamine react then nylon 6, 6 comes out as the final product and release 2 molecule of water.

So

M_{repeat}=146.14+166.21-2\times 18.106\ g/mol

M_{repeat}=226.32\ g/mol

So

Mo= 226.32/2 =113.16 g/mol

M_n=X_nM_o

Given that

Mn= 15,000 g/mol

So

15,000 = Xn x 113.16

Xn = 132.55

Now by using Carothers equation we know that

X_n=\dfrac{1+r}{1+r-2rp}

132.55=\dfrac{1+r}{1+r-2\times 0.99r}

By calculating we get

r= 0.9949

For 19,000

19,000 = Xn x 113.16

Xn = 167.99

By calculating in same process given above we get

r=0.995

3 0
3 years ago
What specific electrophile does benzene attack when it undergoes nitration??
Deffense [45]
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(BENZENE) (NITRIC ACID)(CATALYST)
</span>NO2(+) is the electrophile that acctacks on the benzene ring in nitration process.
7 0
3 years ago
How many core electrons are in a ground state atom of selenium?
Harman [31]
Electrons in an atom can be classified as core electrons and valence electrons. Valence electrons are those electrons which are present in valence shell and participates in bond formation. While, Core electrons are all remaining electrons which are not present in valence shell, hence not take part in bonding.

Atomic number of Selenium (Se) is 34 hence it has 34 electrons with following electronic configuration;

                          1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴

From electronic configuration it is found that the valence shell is 4, and the number of electrons present in valence shell are 6. So, 

             Core Electrons  =  Total Electrons - Valence Electrons

             Core Electrons  =  34 - 6

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Result:
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3 0
3 years ago
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