How many moles of NO2 form when
63.25 g N2O5 decompose?
2N2O5→ 4NO2 + 0₂
1 answer:
Answer:
1.1713 moles
Explanation:
RFM of N2O5= (14*2)+(16*4)=108
Moles of N2O5= Mass/RFM= 63.25/108= 0.5856 moles
Mole ratio of N2O5:NO2 = 2:4
Therefore moles of NO2= 4/2*0.5856= 1.1713 moles
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