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Olegator [25]
3 years ago
7

If the last three animals of a species are all females, what will happen to the species?

Chemistry
2 answers:
Tcecarenko [31]3 years ago
5 0

Answer:

B

Explanation:

Aliun [14]3 years ago
4 0
The best answer to go with is b
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hi

Explanation:

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What does a steam engine do?
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B steam causes wheels to turn is correct
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3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
Can someone help me please
Tanya [424]
I believe that the correct answer would be energy since you need energy for any kind of chemical change to occur. I hope this helped you with your question! If you have any questions please let me know and I might be able to further assist you.
6 0
3 years ago
What is the composition and percentage of the gases in earths atmosphere?
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Nitrogen accounts for 78% of the atmosphere, oxygen 21% and argon 0.9%. Gases like carbon dioxide, nitrous oxides, methane, and ozone are trace gases that account for about a tenth of one percent of the atmosphere.

3 0
2 years ago
Read 2 more answers
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