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zlopas [31]
3 years ago
5

A boat moves through the water with two forces acting on it. One is a 2.51×103 N forward push by the motor, and the other is a 1

.88×103 N resistive force due to the water. What is the acceleration of the 1384.1 kg boat? Answer in units of m/s 2
Physics
1 answer:
telo118 [61]3 years ago
7 0

Answer:

Acceleration a=0.455m/sec^2

Explanation:

We have given that the force by the motor F=2.51\times 10^3N=2510N

Resistive force by the water F=1.88\times 10^3N=1880N

So net force F_{NET}=2510-1880=630N

Mass of the boat = 1384.1 kg

According to newton's second law F=Ma, here M is mass and a is acceleration

So 630=1384.1\times a

a=0.455m/sec^2

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Marat540 [252]

Answer:

147.7 N

221.55 Nm

Explanation:

P = Pressure = 100000 Pa

R_s = Mass-specific gas constant = 287.015 J/kg k

T = Temperature = 10+273 = 283 K

C = Drag coefficient = 1.1

A = Area

r = Radius = 0.2 m

v = Speed of wind = \frac{150}{3.6}\ m/s

L = Length of pole

Density

\rho=\frac{P}{R_sT}\\\Rightarrow \rho=\frac{100000}{287.058\times 283}\\\Rightarrow \rho=1.2309\ kg/m^3

Drag force

F=\frac{1}{2}\rho CAv^2\\\Rightarrow F=\frac{1}{2}\times 1.2309\times 1.1\times \left(\pi \times 0.2^2\right)\times \left(\frac{150}{3.6}\right)^2\\\Rightarrow F=147.7\ N

Force on the circular sign is 147.7 N

M=F\times L\\\Rightarrow M=147.7\times 1.5\\\Rightarrow M=221.55\ Nm

Bending moment at the bottom of the pole is 221.55 Nm

6 0
3 years ago
in the system to the right, the pulleys are frictionless and the system hangs in equilibrium. Determine the values of each of th
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Look up pulleys problem through Khan academy and a video should pop up with a problem similar and you should be able to walk through it .
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The flashlight is powered by one or more batteries.
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Acc= vf-vi/time=10-0/20= 0.5 m/s/s
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A brick of mass 4 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3 cm. The spring is t
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Answer:

Explanation:

Let s be displacement from equilibrium position . Restoring force

m d²s / dt² = - k s

d²s / dt² = - k /m  s

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