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zlopas [31]
2 years ago
5

A boat moves through the water with two forces acting on it. One is a 2.51×103 N forward push by the motor, and the other is a 1

.88×103 N resistive force due to the water. What is the acceleration of the 1384.1 kg boat? Answer in units of m/s 2
Physics
1 answer:
telo118 [61]2 years ago
7 0

Answer:

Acceleration a=0.455m/sec^2

Explanation:

We have given that the force by the motor F=2.51\times 10^3N=2510N

Resistive force by the water F=1.88\times 10^3N=1880N

So net force F_{NET}=2510-1880=630N

Mass of the boat = 1384.1 kg

According to newton's second law F=Ma, here M is mass and a is acceleration

So 630=1384.1\times a

a=0.455m/sec^2

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Answer:

we have formula of frequency :

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for wavelength we swipe it with frequency as follows

λ=c/f

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3 years ago
A cubic sample of a new kind of artificial tissue is subject to an increase in pressure of 160 kPa which results in a reduction
grin007 [14]

Answer:

0.82 MPa

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2 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

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tan\theta = \frac{v^2}{Rg}

here we know that

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tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

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F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

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Answer:

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