Question

You are looking down on a N = 24 turn coil in a magnetic field B = 1 T which points directly down into the screen. If the diameter of the coil d = 3.7 cm, and the field goes to zero in t = 0.08 seconds, what would be the magnitude of the voltage (in Volts) and direction of the induced current? Indicate the direction of the current by the sign in front of your voltage: counterclockwise is positive, clockwise is negative.

Answer 1

Answer:

E = 0.3225 Volts

Explanation:

Given:

N = 24 turns

magnetic field, B = 1 T

Diameter of the coil, d = 3.7 cm = 0.037 m

area, A = $\frac{\pi d^2}{4}$ = $\frac{\pi (0.037)^2}{4}=0.00107\ m^2$

Time, t = 0.08 seconds

Now, The induced Emf (E) is given as;

E = -d(flux)/dt

now, the flux is given as:

Flux = NBA = 24 × 1 × 0.00107 = 0.0258 Wb

Now, E = -0.0258/0.08

or

E = 0.3225 Volts

The current is opposite to the flux, thus the direction of the current will be anti-clockwise