Question

A brick of mass 4 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3 cm. The spring is then stretched an additional 2 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g=980 cm/s^2.
Set up a differential equation with initial conditions describing the motion and solve it for the displacement s(t) of the mass from its equilibrium position (with the spring stretched 3 cm).

Answer 1

Answer:

Explanation:

Let s be displacement from equilibrium position . Restoring force

m d²s / dt² = - k s

d²s / dt² = - k /m  s

Put k /m  = ω

d²s / dt² + ω² s = 0

The solution of this differential equation

= s = A cosωt

Now when t = 0 ,  s = 2 cm

A =  2 cm

Putting the values we have

2 = A cos 0

A = 2 cm

s ( t) = 2 cos ωt