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amid [387]
3 years ago
10

Salt (NaCl) is _____. an acid a base a neutral

Chemistry
1 answer:
Marta_Voda [28]3 years ago
5 0
A neutral isthe correct option
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If an element is lustrous, brittle, and a semi-conductor, how would you classify it?
just olya [345]

Metalloid

Explanation:

If an element is lustrous, brittle and a semi-conductor, it is best classified as a metalloid.

Metalloids shares attributes of metals and non-metals.

  • They are often described as semi-metals as they do not share the full properties that makes a metal a metal.
  • Metalloids are lustrous but not malleable like metals.
  • They do not conduct electricity but they do so on certain conditions.
  • Examples are silicon, germanium, boron, arsenic e.t.c
  • They are usually found in the middle of the periodic table.
  • They are not readily alloyed with metals.

Learn more:

Metalloid brainly.com/question/3023499

#learnwithBrainly

7 0
3 years ago
What happens when sodium and chlorine react to make table salt <br><br> Please help
Julli [10]
When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable. The reaction is extremely exothermic, producing a bright yellow light and a great deal of heat energy.
6 0
3 years ago
Which element has 21 neutrons and 20 electrons?
mario62 [17]
Scandium has 21 neutrons
6 0
3 years ago
Read 2 more answers
PLS HELP: CHEMISTRY
user100 [1]

Answer:

3.59x10^21 molecules

Explanation:

1mole of a substance contains 6.02x10^23 molecules.

Therefore, 1mole of C8H18 will also contain 6.02x10^23 molecules

1mole of C8H18 = (12x8) +(18x1) = 96 + 18 = 114g.

1mole (i.e 114g) oh C8H18 contains 6.02x10^23 molecules.

Therefore, 0.68g of C8H18 will contain = (0.68 x 6.02x10^23)/114 = 3.59x10^21 molecules

7 0
3 years ago
What is the balanced symbol equation for magnesium chloride + sodium carbonate --&gt; magnesium carbonate + sodium chloride
Semenov [28]

Answer:

MgCl₂+ Na₂CO₃ ==> MgCO₃ + NaCl

From a quick observation

You see that the right hand side of the eqn is deficient of Sodium and Chlorine

Simply Add a Coefficient of 2 to NaCl to balance it with the left.

Your answer now becomes

MgCl₂ + Na₂CO₃ ==> MgCO₃ + 2NaCl.✅

3 0
3 years ago
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