The final speed of the electron is 4.64 * 10^5 m/s.
<h3>What is the speed of the electron?</h3>
Given that the mass of the electron is obtained as 9.11 * 10^-31 Kg, we have that the charge of the electron is 1.6 * 10^-19 C.
E= F/q
F = Eq
F = 330 N/C * 1.6 * 10^-19 C
F = 5.28 * 10^-17 N
F = ma
a = F/m = 5.28 * 10^-17 N/ 9.11 * 10^-31 Kg
a = 5.8 * 10^13 m/s^2
Using
v = u + at
u = 0 m/s because the electron was initially at rest
v = at
v = 5.8 * 10^13 * 8.00 ✕ 10−⁹ s
v = 4.64 * 10^5 m/s
Learn more about the speed of the electron:brainly.com/question/13130380
#SPJ1
Answer:
1.776 x 10^-19 m
Explanation:
Energy, E = 7 TeV
Let λ be the wavelength.
Energy = h c / λ
Where, h is the Planks,s constant and c be the velocity of light
h = 6.63 x 10-^-34 Js
c = 3 x 10^8 m/s
Convert TeV into J
1 TeV = 1.6 x 10^-7 J
So, E = 7 x 1.6 x 10^-7 = 11.2 x 10^-7 J
11.2 x 10^-7 = (6.63 x 10^-34 x 3 x 10^8) / λ
λ = 1.776 x 10^-19 m
Answer: <u>D. An AC circuit</u>
Explanation:
I took it on a test and it was correct ; )
Answer:
3 * 10³J/s
Explanation:
Given :
Force applied, F = 300 N
Distance, d = 30 m
Time, t = 3 seconds
Power, P = Workdone / time
Recall :
Workdone = Force * distance
Workdone = 300 N * 30 m = 9000 Nm
Workdone = 9 * 10³ J
Power = (9 * 10³ J) / 3s
Power = 3 * 10³J/s
