Answer:
\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}
Explanation:
0.030 cm³ × ? = x m³
You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.
For example, you know that centi means "× 10⁻²", so
1 cm = 10⁻² m
If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).
If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.
So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.
We choose the former because it has the desired units on top.
The "cm" is cubed, so we must cube the conversion factor.
The calculation becomes

Ir = [Xe] 4f14 5d7 6s2
<span>Rn = [Xe] 4f14 5d10 6s2 6p6 </span>
<span>Fe = [Ar] 3d6 4s2 </span>
<span>Pa = [Rn] 5f2 6d1 7s2 </span>
<span>Y = [Kr] 4d1 5s2 </span>
<span>Re = [Xe] 4f14 5d5 6s2 </span>
<span>So only Rhenium (Re) has an electronic configuration where the d orbital has 5 electrons in it.</span>
About 22 45 88 102 points percent and adding