Answer:
a. 5.77L
b. 700mmHg
c. 395K
Explanation:
Using PV = nRT we can solve these problems where:
P is pressure of the gas in atm (1atm = 760mmHg)
V is volume in liters
n are moles of the gas
R is gas constant: 0.082atmL/molK
T is asbolute temperature in K
a. PV = nRT
V = nRT/P
P = 773mmHg*(1atm/760mmHg) = 1.017atm
T = 25°C+273 = 298K
V = 0.240mol*0.082atmL/molK*298K / 1.017atm
V = 5.77L
b. PV = nRT
P = nRT/V
P = 0.0947mol*0.082atmL/molK*309K/0.635L
P = 0.9216atm * (760mmHg/1atm) = 700mmHg
c. PV = nRT
PV/nR = T
P = 727mmHg * (1atm / 760mmHg) = 0.9566atm
0.9566atm*13.3L/0.393mol*0.082atmL/molK = T
T = 395K
Answer:
it's a precipitation reaction.
Explanation:
since a solid is produced, one of the elements are insoluble with one another–making a precipitate.
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:
PbI2 = Pb^2+ + 2I-
We solve as follows:
Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
</span><span>1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M
The molar solubility would be </span>1.5x10^-3 M.
