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Vladimir79 [104]
3 years ago
15

A compound has the empirical formula ch and a formula mass of 52.10 amu. part a what is the molecular formula of the compound?

Chemistry
2 answers:
a_sh-v [17]3 years ago
7 0

Answer: The 3rd option (CH4) on edg

Explanation:

Sever21 [200]3 years ago
3 0
<span>C4H4 The compound in question has an equal ratio of hydrogen and carbon. The atomic weight of carbon is roughly 12 and the atomic weight of hydrogen is roughly 1. The mass of the compound in question is roughly 52. 52/13=4 C4H4</span>
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A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
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The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

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