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Agata [3.3K]
3 years ago
15

Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.

Chemistry
1 answer:
Mazyrski [523]3 years ago
3 0
1)
 HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻
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Among the following, which is NOT an ionic compound?<br> Ca3N2<br> N204<br> AICI:<br> NaCl
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The tert-butyl chloride in ethanol would surely react faster than the solvolysis of 1-chloro-2,2-dimethyl propane. It is known that both reactions are under the SN2 category so it would be hard for these reactions to occur. However, SN1 reactions are possible because of the ethanol which is a polar solvent. Both would form carbocations but tert-butyl chloride forms a more stable carbocation while the 1-chloro-2,2-dimethyl propane forms a primary carbocation only. 
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In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.
mihalych1998 [28]

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

8 0
3 years ago
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