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3 years ago

Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.

1 answer:

3 0

1)
HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻

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Explain how a light ray behaves when it strikes a mirror?

Vinvika [58]

The light ray is reflected when it his a mirror.

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3 years ago

Read 2 more answers

A copper ore containing 4.3 wt% water, 10.3 wt% CuSO, and 85.3 wt% rock is fed to a staged counter current extractor at a rate o

Serga [27]

Answer:

6 stages

Explanation:

Given:

Copper ore contains:

4.3 wt% water

10.3 wt% CuSO₄

85.3 wt% rock

Feed rate = 11.7 tons per hour

solution produced is to be 10 wt% copper sulfate

90 wt% water

Now,

The CuSO₄ supplied through the feed = 10.3 wt% CuSO₄ × Feed rate

= 0.103 × 11.7

= 1.2051 tons per hour

also,

At each stage 2 tons of solution is collected

therefore,

The CuSO₄ collected in each stage

= weight of solution × 10 wt% copper sulfate

= 2 tons per hour × 0.1

= 0.2 tons per hour

also,

98% of the CuSO₄ is to be recovered

thus,

the amount of CuSO₄ to be recovered

= 0.98 × CuSO₄ supplied through the feed

= 0.98 × 1.2051 tons per hour

= 1.180998

Therefore,

The number of stages required = $\frac{\textup{amount of CuSO₄ to be recovered }}{\textup{CuSO₄ collected in each stage }}$

= $\frac{\textup{1.180998}}{\textup{0.2}}$

= 5.90499 ≈ 6 stages

8 0

4 years ago

why do you think you can find silver and gold on their own in rocks but calcium and magnesium are combined with other elements t

katrin [286]

Explanation:

Silver and Gold belong to a special group of metals known as the native metals. They are found naturally on their own and not in combined form in rocks.

These metals are found uncombined because they are unreactive.
They prefer to alloy with themselves.
Calcium and magnesium on the other hand are reactive metals.
The unreactivity of these metals makes them uncombined in nature.

4 0

3 years ago

Read 2 more answers

HNO3 + S --> H2SO4 + NO Now identify the element oxidized and the element reduced. Which element is oxidized? Which element i

OleMash [197]

Answer: S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

$HNO_3+S\rightarrow H_2SO_4+NO$

On the reactant side:

Oxidation number of H = +1

Oxidation number of N = +5

Oxidation number of O = -2

Oxidation number of S = 0

On the product side:

Oxidation number of H = +1

Oxidation number of N = +2

Oxidation number of O = -2

Oxidation number of S = +6

As the oxidation number of S is increasing from 0 to +6. Thus, it is getting oxidized. Similarly, the oxidation number of N is decreasing from +5 to +2. Thus, it is getting reduced.

The oxidation numbers of O and H remain the same on both sides of the reaction. Thus, they are neither getting oxidized or reduced.

Hence, S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

3 0

3 years ago

HELP ME PLEASE (brainliest)

Aloiza [94]

Answer: i would say D or the last one.

Explanation: According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Hope this helps :) Can u plz mark me branliest

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2 years ago