The Nobel gasses
Excluding those, the most active are the lower left and upper right.So the least
active (EXCLUDING GROUP 18) are the non- metals furthest form the upper right
If that in the middle between the 10 and 24 is a caret, then I believe this is the work:
3.6 x 10^24 atoms Zn / 6.022x10^23 atom/mol Zn = 6 mol Zn
6 mol Zn x 65.36 g/mol Zn = 390 g Zn if you carry two significant figures with rounding at each step.
I believe that is correct as all the units cancel properly.
Answer:
Bq/m3 (becquerels per cubic meter) or pCi/l (picocuries per litre)
Explanation:
The unit of the International System of Units identified to measure radioactive activity is Becquerelio (Bq) and equivalent to one decay per second.
The Curio (Ci) is also a radioactivity unit, which is still being used in some countries. It owes its name to chemists and chemists Pierre and Marie Curie.
It represents the amount of material in which 3.7 × 1010 atoms per second, or 3.7 × 1010 nuclear decays per second, which is roughly the activity of 1 g of 226Ra (isotope of the chemical chemical element).
The equivalence between the two is:
1Ci= 3,7 × 1010Bq
The specific radioactive activity of a radioactive gas such as radon gas is measured per unit volume and measured in Bq/m3 or pCi/l.
In this case the equivalence is:
1pCi/l= 37Bq/m3
Answer:
1. 389 kJ; 2. 7.5 µg; 3. 6.25 days
Explanation:
1. Energy required
The water is converted directly from a solid to a gas (sublimation).
They don't give us the enthalpy of sublimation, but
The equation for the process is then
Mᵣ: 18.02
46.69 kJ + H₂O(s) ⟶ H₂O(g)
m/g: 150
(a) Moles of water
(b) Heat removed
46.69 kJ will remove 1 mol of ice.
2. Mass of water vapour in the freezer
For this calculation, we can use the Ideal Gas Law — pV = nRT
(a) Moles of water
Data:
V = 5 L
T = (-80 + 273.15) K = 193.15 K
Calculation:
(b) Mass of water
3. Time for removal
You must remove 150 mL of water.
It takes 1 h to remove 1 mL of water.
