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Tanya [424]
3 years ago
7

What kind of elements are on the left side of the zig-zag line on the periodic table?

Chemistry
1 answer:
Ber [7]3 years ago
3 0

Metals are to the left of the zig-zag, nonmetals are to the right, and metalloids lie on/beside the line.

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Pentaborane-9, B5H9, is a colorless, highly reactive liquid that will burst into flame when exposed to oxygen. The reaction is 2
mina [271]

<u>Answer:</u> The amount of energy released per gram of B_5H_9 is -71.92 kJ

<u>Explanation:</u>

For the given chemical reaction:

2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(5\times \Delta H^o_f_{(B_2O_3(s))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(2\times \Delta H^o_f_{(B_5H_9(l))})+(12\times \Delta H^o_f_{(O_2(g))})]

Taking the standard enthalpy of formation:

\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol\\\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(5\times (1271.94))+(9\times (-285.83))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H^o_{rxn}=-9078.57kJ

We know that:

Molar mass of pentaborane -9 = 63.12 g/mol

By Stoichiometry of the reaction:

If 2 moles of B_5H_9 produces -9078.57 kJ of energy.

Or,

If (2\times 63.12)g of B_5H_9 produces -9078.57 kJ of energy

Then, 1 gram of B_5H_9 will produce = \frac{-9078.57kJ}{(2\times 63.12)}\times 1g=-71.92kJ of energy.

Hence, the amount of energy released per gram of B_5H_9 is -71.92 kJ

8 0
3 years ago
If you are running at top speed and try to stop suddenly, what happens?
vlada-n [284]

You are going to fall, face first on the ground.

7 0
2 years ago
I need help please this is my final
aliina [53]

Answer:

hmm fart

Explanation:

yep my final

8 0
2 years ago
What is the equilibrium constant of a reaction?
xeze [42]

Answer:

A. It is the ratio of the concentrations of products to the concentrations of reactants.

Explanation:

The equilibrium constant of a chemical reaction is the ratio of the concentration of products to the concentration of reactants.

This equilibrium constant can be expressed in many different formats.

  • For any system, the molar concentration of all the species on the right side are related to the molar concentrations of those on the left side by the equilibrium constant.
  • The equilibrium constant is a constant at a given temperature and it is temperature dependent.
  • The derivation of the equilibrium constant is based on the law of mass action.
  • It states that "the rate of a chemical reaction is proportional to the product of the concentration of the reacting substances. "
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For the following exothermic reaction, A+B⇌C+D + Heat, if the temperature is increased, the reaction will experience a shift to
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(Left) I’m pretty sure
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