The distance to a lightning bolt can be determined by counting the seconds between the flash and the sound of thunder due to the speed of light is greater than the speed of sound
We must consider that the speed of light (3.00× 10⁸ m/s) is greater than the speed of sound (340 m/s), this is why we can first see the lightning and after seeing it we can hear it.
In order to calculate the distance we must count the time since the lightning bolt and use the speed of sound, applying the following formula:
x = v * t
Where:
- x = distance
- t = time
- v = velocity
<h3>What is velocity?</h3>
It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
Learn more about velocity at: brainly.com/question/80295?source=archive
#SPJ4
Answer:
For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation:
-- If acceleration and velocity are in the same direction,
then the object is speeding up.
-- If acceleration and velocity are in opposite directions,
then the object is slowing down.
-- If acceleration is perpendicular to velocity, then the object
is moving on a circular curve at constant speed.
Answer:
a) x = 660 m
, b) λ = 0.330 m
, c) precision is 0.1 cm
, d) Δf= n Δt/ t²
Explanation:
a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is
v = x / t
x = v t
x = 330 2
x = 660 m
b) the speed of sound is
v = λ f
λ = v / f
λ = 330/1000
λ = 0.330 m
c) a measuring tape must be used to measure the wavelength, the precision is 0.1 cm
.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency
.f = n / t
Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s
Δf / f = Δt / t
Δf = Δt /t f
Δf= n Δt/ t²
