Answer:
1)
2)
Explanation:
Given:
- mass of heavier student,
- mass of lighter student,
- velocity of the heavier student after the mutual push,
1)
Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.
Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.
2)
<u>From the condition of elastic collision:</u>
Resistance of a lightbulb is 240.8 ohm
Given:
Power = 120 W
Frequency = 60.0-Hz
Voltage = 170 V
To Find:
Resistance of a lightbulb
Solution: The electrical resistance of a circuit is the ratio between the voltage applied to the current flowing through it. Rearranging the above relation, R = V I. The unit of electrical resistance is ohms.
The resistance of the light bulb is given by the formula, R=V²/P
R = (170)^2/120
R = 240.8 ohm
Hence, the resistance of light bulb is R = 240.8 ohm
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Answer:
She was obese and had a diet high in salt intake.
Explanation:
higher blood pressure is condition known as hypertension which is the main cause of many heart problems which can be life threatening. In obese people. high level of fats inside the blood vessels which can cause blockage inside and can lead to heart problems.
high concentration of salts intake also disturbs the salts concentration in the blood vessels. The disturbance in salt concentration is the function of the kidney to remove it. the increase concentration also cause increase in blood pressure which leads to hypertension.
He is the lead singer of the band Queen.
Answer:
v₂ = 63.62 m / s
Explanation:
For this exercise in fluid mechanics we will use Bernoulli's equation
P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂
where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.
We will assume that the distance between the two parts is small, so y₁ = y₂
P₁-P₂ = ρ g (v₂² - v₁²)
pressure is defined by
P = F / A
we substitute
ΔF / A = ρ g (v₂² - v₁²)
v₂² =
suppose that the area of the wing is A = 1 m²
we substitute
v₂² =
v₂² = 79.10 + 3969
v₂ = √4048.1
v₂ = 63.62 m / s