Answer:
a) v = 19,149.6 m/s
b) f = 95%
c) t = 346.5min
Explanation:
First put all values in metric units:
The equation of motion you need is:
where 
is the final velocity, a is acceleration and t is time in hours.
Since the spaceship starts from 0 velocity:
Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:
solving for first and last interval:
Since the spaceship starts and finish with 0 velocity:
Then the ship traveled 
at constant speed, which means that it traveled:
Which in percentage is 95% of the trip.
to calculate total time you need to calculate the time used during constant speed:
That added to the other interval times:
Answer:
0.28 m
Explanation:
The following data were obtained from the question:
Force (F) = 5×10¯⁶ N
Charge 1 (q₁) = 6.7×10¯⁹ C
Charge 2 (q₂) = 6.7×10¯⁹ C
Electrical constant (K) = 9×10⁹ Nm²C¯²
Distance apart (r) =?
Thus, the distance between the two charges can be obtained as follow:
F = Kq₁q₂/r²
5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²
5×10¯⁶ = 4.0401×10¯⁷ / r²
Cross multiply
5×10¯⁶ × r² = 4.0401×10¯⁷
Divide both side by 5×10¯⁶
r² = 4.0401×10¯⁷ / 5×10¯⁶
Take the square root of both side
r = √(4.0401×10¯⁷ / 5×10¯⁶)
r = 0.28 m
Therefore, the distance between the two charges is 0.28 m
Answer:
a
The x- and y-components of the total force exerted is
b
The magnitude of the force is
The direction of the force is
Clockwise from x-axis
Explanation:
From the question we are told that
The magnitude of the first charge is 
The magnitude of the second charge is 
The position of the second charge from the first one is 
The magnitude of the third charge is 
The position of the third charge from the first one is 
The position of the third charge from the second one is
The force acting on the third charge due to the first and second charge is mathematically represented as
Substituting values
The magnitude of 
is mathematically evaluated as
The direction is obtained as
![\theta = tan ^{-1} [-0.63889]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B-0.63889%5D)
Answer:
The effect of gravitation is more in liquid than on solid because inter molecular force of attraction is less in liquid and it is weak than that of solid. ... Whereas in solid the molecule are densely packed together an the inter molecular forces are constantly acting upon one another, this results in higher forces.
