Question

When responding to sound , the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 6.3×10−7m and a maximum speed of 2.9×10−3m/s. (a) What is the frequency (in Hz) of the eardrum' s vibration? (b) What is the maximum acceleration of the eardrum?

Answer 1

Answer:

a) The frequency of the eardrum's vibration is 732.62 Hz.

b) The maximum acceleration of the eardrum is 13.35 m/s².

Explanation:

a) The maximum speed of a vibration is given by:

$V_{max}=A\times \omega=A\times2\pi f$

where:

A is the  amplitude of the wave

f is the frequency of the wave

Then,

$V_{max}=A\times2\pi f\\f= \frac{V_{max}}{A\times 2\pi} \\f= \frac {2.9\times 10^{-3}\frac{m}{s}} {6.3\times 10^{-7}m\times2\pi }\\f=732.62 Hz$

b) The maximum acceleration of a vibration is given by:

$a_{max}=A\times \omega^2=A\times(2\pi f)^2\\a_{max}=6.3\times 10^{-7}m \times (2\pi\times 732.62 s^{-1} )^2\\a_{max}= 13.35 \frac{m}{s^2}$

Answer 2

Answer:

idk

Explanation: