The current loop lies flat on a horizontal surface. Facing the loop from the top, the current moves in a clockwise direction. Wh
1 answer:
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Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that the friction force on two boxes is given as
Now we know by Newton's II law
so we have
Part b)
For block B we know that net force on it will push it forward with same acceleration so we have
Part c)
If Alex push from other side then also the acceleration will be same
So for box B we can say that Net force is given as
Answer:
43.16°
Explanation:
λ = Wavelength = 1.4×10⁻¹⁰ m
θ₁ = 20°
n can be any integer
d = distance between the two slits
Since for the first bright fringe, n₁ = 1
n₂ = 2 for second order line
The relation between the distance of the slits and the angle through which it is passed is:
dsinθ=nλ
As d and λ are constant
∴ Angle by which the second order line appear is 43.16°