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Answer:
If it is triple it means we multiply it by 3 then it is 36.3 m/s/s
Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration ![a=5.56m/sec^2](https://tex.z-dn.net/?f=a%3D5.56m%2Fsec%5E2)
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion ![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
Putting all values in equation
![278^2=0^2+2\times 5.56\times s](https://tex.z-dn.net/?f=278%5E2%3D0%5E2%2B2%5Ctimes%205.56%5Ctimes%20s)
s = 6950 m
So distance traveled during this acceleration will be 6950 m
Answer:
An object that is moving wants to stay moving in a straight line. It takes an outside force acting upon it to change its direction or cause an acceleration.
Explanation: